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ollegr [7]
3 years ago
9

Please help me with this math problem. (It's a multiple choice question btw)

Mathematics
2 answers:
sleet_krkn [62]3 years ago
5 0
The 1st box
The 2nd box
The 5th box.
Hope this helps.
GuDViN [60]3 years ago
3 0
315 divided by 1700 can be demonstrated in a few ways. 

Choice 1 315


------

1700
, Choice 2 and Choice 5: 315÷1700


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The sensitive period for language is from 7 months in utero up to 5.5 to 6 years of age. There are several aspects of language f
OleMash [197]

Answer:

The sensitive period for language is from 7 months in utero up to 5.5 to 6 years of age. There are several aspects of language from spoken language, to written language and reading. ... The sensitive period for learning to speak is from is from 7 months to 2.5-3 years of age.

Step-by-step explanation:

7 0
3 years ago
Seven less than the product of 5 and a number is 2
slava [35]

5x-7=2

hope this makes sense

6 0
4 years ago
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Y=2(x-1)^2+1 in standard form
Ronch [10]

Answer:

2(x^2+1-2x)+1=

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Step-by-step explanation:

7 0
3 years ago
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Please help ASAP! Correct answer only! This assignment is due today.
astra-53 [7]

Answer:

<em>Probability ≈ 0.0714</em>

Step-by-step explanation:

Consider permutation and combination;

Total Combinations - 8C4,\\8C4 = 8! / 4! * ( 8 - 4 )!,\\8 * 7 * 6 * 5 / 4!,\\\\Total Combinations = 70,\\\\Combinations of Dance Classes - 5C4,\\5C4 = 5! / 4! * ( 5 - 4 )!,\\5 * 4 * 3 * 2 * 1 / 4 * 3 * 2 * 1,\\\\Dance Classes = 5,\\\\Probability - 5 / 70 = 0.0714,\\Conclusion; Probability = ( About ) 0.0714

5 0
3 years ago
Solve for the missing side: simplify the radical ​
Viefleur [7K]

Answer:

x=8\sqrt{5}

Step-by-step explanation:

I will assume the following:

  • You know how to use  the quadratic formula
  • You know how to simplify radicals
  • You know how to use the pythagorean theorem.

The challenge of this exercise comes from using the pythagorean theorem and setting up a few equations.

Given that we have a segment 36 units long and another segment that is 16, it is trivial to get the other segment, 20. Additionally, there are two sides that I want to name so that way I can make a couple of substitutions. I will call these side a and side b. (see attachment 1)

Now comes with setting up three equations. I will start with the two smaller triangles, using side a and side b. See attachments 2 and 3.

Now with the big triangle. I will set up one last equation. See attachment 4.

Given what we know about attachment 2 and 3, we can make two substitutions. See attachment 5. I assume you know how to do the rest and arrive at your only real solution.

5 0
3 years ago
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