Answer: y = 6280(0.87)^x
Step-by-step explanation:
If the office equipment depreciates at a rate of 13% each year, then the rate of depreciation is exponential.
We would apply the formula for exponential decay which is expressed as
y = b(1 - r)^x
Where
y represents the value of the office equipment after t years.
x represents the number of years.
b represents the initial value of the office equipment.
r represents rate of decay.
From the information given,
y = $628
r = 13% = 13/100 = 0.13
Therefore, the equation that represents the value of the equipment after x years is
y = 6280(1 - 0.13)^x
y = 6280(0.87)^x
Catalog # Size Package Content Price* Qty
BR1400106 6 reactions of 50 µl Reagents for coupled transcription/translation reactions
€196.00
0
BR1400101 24 reactions of 50 µl Reagents for coupled transcription/translation reactions
€591.00
0
BR1400102 96 reactions of 50 µl Reagents for coupled transcription/translation reactions
€1,864.00
Answer:
Step-by-step explanation:
So, we started out with 128 ounces of milk.
Each day, Joann drinks 14 ounces of milk.
Therefore, the amount of milk left over after x days is 14 times x subtracted from 128.
Therefore, our function is:
And we're done!
The key is Esther travelled the same distance - x - in both her morning and evening commute.
45(time she took in the morning, or p) = x
30(time she took in the evening, or q) = x
Therefore 45(p) = 30(q), or divide both sides by 5 and get 9(p) = 6(q). I know you can divide it further, but these numbers are small enough and it's not worth the time.
Since the whole trip took an hour, (p + q) = 60min, and so, p = 60-q.
Therefore 9(60-q) = 6q or 540-9q = 6q. So 540 = 15q, which makes q = 36. If q = 36, then by (p+q)=60, p (the time she took in the morning) must equal 24.
45 miles per hour, her speed in the morning, times (24/60) hours, her time, makes 18 miles travelled in the morning. If you check, 30 miles per hour times (36/60) hours also makes 18 miles in the evening.
<span>Hope that makes a little sense. And I also hope it's right</span>
