Answer:
When we have a function f(x), the average rate of change in the interval (a, b) is:

In this case, we have the function:
f(x) = (x + 3)^2 - 2
(but we do not have the interval, and I couldn't find the complete question online)
So if for example, we have the interval (2, 4)
The average rate of change will be:

If instead, we want the rate of change in a differential dx around the value x, we need to differentiate the function (this is way more complex, so I will define some rules first).
Such that the rate of change, in this case, will be:
f'(x) = df/dx
For a function like:
g(x) = x^n + c
g'(x) = n*x^(n - 1)
And for:
h(x) = k( g(x))
h'(x) = k'(g(x))*g'(x)
So here we can write our function as:
f(x) = k(g(x)) = (x + 3)^2 - 2
where:
g(x) = x + 3
k(x) = x^2 - 2
Then:
f'(x) = 2*(x + 3)*1 = 2*x + 6
That is the rate of change as a function of x (but is not an "average" rate of change)
Answer: 36
Step-by-step explanation:
Answer:
9216
Step-by-step explanation:
number of small cubes that would fill the prism = volume of prism / volume of small cubes
volume of a prism = length x width x height
3 x 6 x 8 = 144
volume of cube = length³
(1/4)³ = 1/64
144 ÷ 1/64
144 x 64 = 9216