Answer:
P(X is greater than 30) = 0.06
Step-by-step explanation:
Given that:
Sample proportion (p) = 0.5
Sample size = 30
The Binomial can be approximated to normal with:
To find:
P(X> 30)
So far we are approximating a discrete Binomial distribution using the continuous normal distribution. 30 lies between 29.5 and 30.5
Normal distribution:
x = 30.5, 
= 25, 
= 3.536
Using the z test statistics;
z = 1.555
The p-value for P(X>30) = P(Z > 1.555)
The p-value for P(X>30) = 1 - P (Z< 1.555)
From the z tables;
P(X> 30) = 1 - 0.9400
Thus;
P(X is greater than 30) = 0.06
6x-15=3(4x+3)
Distribute the three to the parentheses
6x-15=12x+9
Transfer the 6 over to the 12 by subtracting it
-15=6x+9
Subtract 9 from 15
-24=6x
Then divide the six by the -24
X=-4
To get the probability of two individual events both occurring,
you have to multiply the probabilities of their individual events occurring. Therefore
in this problem, the probability that a student selected at random will pass
both French 101 and French 102 is 0.683 (.75 x .91). The answer is already
rounded to three decimal places.
Answer:
B
Step-by-step explanation:
Answer: x+y = 40
We have a = 1, b = 1, c = 40
=================================
Explanation:
x = number of nickels
y = number of quarters
The equation 0.05x+0.25y = 5 represents adding the values from the nickels and quarters
0.05x = value of just the nickels
0.25y = value of just the quarters
0.05x+0.25y = total value = 5 dollars
That's how that first equation was formed.
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Based on those x and y definitions above, we know that x+y = 40 because there are 40 coins of either nickels or quarters only. So the sum of the two coin counts must be 40 overall.
The equation x+y = 40 is the same as 1x+1y = 40. This equation is in the form ax+by = c where,
a = 1
b = 1
c = 40
