Answer:
Justin's average speed to his parents' house: x= 40mph
Justin's average speed from his parents' house: x+20=60 mph
Step-by-step explanation:
Let the average speed be x +20
Then average speed from his parents' x
And the distance is S=96
Then we know :

Justin's average speed to his parents' house: x= 40mph
Justin's average speed from his parents' house: x+20=60 mph
(3*z) +13
I believe this is correct
Given sequence:
56, 63, 70,..., 329
First find the common difference:
d=a2-a1
d=63-56
d=7
Formula:
an=a1+(n-1)d
First find the number of terms.
329=56+(n-1)7
329=56+7n-7
329=49+7n
280=7n
40=n
or
n=40
We have to find 40-11=29 th term ( 11 th term from the end)
a29= 56+(29-1)7
a29=56+(28)7
a29=56+196
a29=252
Answer: 252 is 11th term from the end.