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Sveta_85 [38]
3 years ago
11

Problem solving multiplication

Mathematics
2 answers:
antoniya [11.8K]3 years ago
5 0
Multiplication word problems arise in situations where we do repeated addition of the same number. Think of multiplication as a shortcut for adding the same number multiple times.
Cerrena [4.2K]3 years ago
3 0
With what you just said problem with solving multiplication
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12.Se consideră mulţimile A={3x-1, 2x+1, 4x+2} şi B={x+1, x+2, 2x+4} unde x ∈ N. Valoarea lui x pentru
Artyom0805 [142]

Answer:

which language is this????

3 0
3 years ago
2 whole 2/3 times 3/11
sashaice [31]
2 2/3 x 3/11
= 8/4 x 3/11
= 24/44
Simplified
6/11
3 0
3 years ago
15 + 4x = 12 + x nm jjk kj k j jk kj k kj kjkj
Marta_Voda [28]

Answer:

x = −1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

8 0
3 years ago
Can someone help me please
denpristay [2]

Area of rhombus = length x height = 6 x 4 = 24 units²



Answer: 24 units²

4 0
3 years ago
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