Standard Equation for trig function: y = A cos (B (x - H))+ K
*Here, we are just dealing with A (amplitude) and B (period)
Period = 2π/ b
8 = 2π/ b
Solve for b: 2π/8 or π/4
Equation: y = 2 cos (π/4 (x))
Answer:
41.8887 cm^2
Step-by-step explanation:
area of a circle
A = pi * r^2
A = pi * (3 + 4)^2
A = pi * 49
A = 153.94
120 / 360 = 1/3
153.94 / 3 = 51.3134
now area of inner circle
A = pi * 3^2
A = pi * 9
A = 28.274
28.274 / 3 = 9.4247
subtract
51.3134 - 9.4247 = 41.8887
Answer:
a = 4
Step-by-step explanation:
a^2 + b^2 = c^2
a= ?
b= 3
c= 5 (c is always the hypotenuse)
*plug in given values
a^2 + 3^2 = 5^2
a^2 + 9 = 25
-9 -9
a^2 = 16
*find the square root
sqrt(a) = sqrt(16)
a = 4
Step-by-step explanation:
<u>Step 1: Substitute x from the second equation into the second one</u>
<u>Step 2: Substitute y into the second equation</u>
Answer: 
