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olchik [2.2K]
3 years ago
6

HELP!!!! I don’t know what to do

Mathematics
1 answer:
Oliga [24]3 years ago
6 0

Answer:

-2

Step-by-step explanation:

the slope is 4/-2

so when you reduce it you get -2

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2/3 * 2/3 divid (2/5 divide 3/5) answer plz
hichkok12 [17]

Answer for Q.1 = 4/9     
Answer for Q2. = 2/3
6 0
3 years ago
The area of the triangle formed by x− and y− intercepts of the parabola y=0.5(x−3)(x+k) is equal to 1.5 square units. Find all p
Juliette [100K]

Check the picture below.


based on the equation, if we set y = 0, we'd end up with 0 = 0.5(x-3)(x-k).

and that will give us two x-intercepts, at x = 3 and x = k.

since the triangle is made by the x-intercepts and y-intercepts, then the parabola most likely has another x-intercept on the negative side of the x-axis, as you see in the picture, so chances are "k" is a negative value.

now, notice the picture, those intercepts make a triangle with a base = 3 + k, and height = y, where "y" is on the negative side.

let's find the y-intercept by setting x = 0 now,


\bf y=0.5(x-3)(x+k)\implies y=\cfrac{1}{2}(x-3)(x+k)\implies \stackrel{\textit{setting x = 0}}{y=\cfrac{1}{2}(0-3)(0+k)} \\\\\\ y=\cfrac{1}{2}(-3)(k)\implies \boxed{y=-\cfrac{3k}{2}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of a triangle}}{A=\cfrac{1}{2}bh}~~ \begin{cases} b=3+k\\ h=y\\ \quad -\frac{3k}{2}\\ A=1.5\\ \qquad \frac{3}{2} \end{cases}\implies \cfrac{3}{2}=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)


\bf \cfrac{3}{2}=\cfrac{3+k}{2}\left( -\cfrac{3k}{2} \right)\implies \stackrel{\textit{multiplying by }\stackrel{LCD}{2}}{3=\cfrac{(3+k)(-3k)}{2}}\implies 6=-9k-3k^2 \\\\\\ 6=-3(3k+k^2)\implies \cfrac{6}{-3}=3k+k^2\implies -2=3k+k^2 \\\\\\ 0=k^2+3k+2\implies 0=(k+2)(k+1)\implies k= \begin{cases} -2\\ -1 \end{cases}


now, we can plug those values on A = (1/2)bh,


\bf \stackrel{\textit{using k = -2}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-2)\left(-\cfrac{3(-2)}{2} \right)\implies A=\cfrac{1}{2}(1)(3) \\\\\\ A=\cfrac{3}{2}\implies A=1.5 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{using k = -1}}{A=\cfrac{1}{2}(3+k)\left(-\cfrac{3k}{2} \right)}\implies A=\cfrac{1}{2}(3-1)\left(-\cfrac{3(-1)}{2} \right) \\\\\\ A=\cfrac{1}{2}(2)\left( \cfrac{3}{2} \right)\implies A=\cfrac{3}{2}\implies A=1.5

7 0
3 years ago
which linear system has been correctly solved for one of the variables from the following system? 2x - y = -1 2x y = -7 2x - y =
mr Goodwill [35]
If you would like to solve the system of linear equations, you can do this using the following steps:

2x - y = -1 ... y = 2x + 1
2x + y = -7 ... y = -7 - 2x

The correct result would be: y = 2x + 1, <span>2x + y = -7.</span>
4 0
3 years ago
I’m so confused I don’t know how to subtract fractions. What is 2+2-1 2/3
Alexxandr [17]

Answer:

its 7/3 or you could put 2 1/3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which pair of numbers have a GCF of 2? Choose all answers that are correct. A. 10 and 2 B. 4 and 6 C. 6 and 12 D. 2 and 24
il63 [147K]
A.
<span>GCF(10; 2) = 2  /</span>factors of 10: 1, 2, 5, 10; factors of 2: 1, 2/

B.
GCF(4; 6) = 2  /factors of 4: 1, 2, 4; factors of 6: 1, <span>2, 3, 6/</span>

C.
GCF(6; 12) = 6  /factors of 6: 1, 2, 3, 6; factors of 12: 1, <span>2, 3, 4, 6, 12/</span>

D.
GCF(2; 24) = 2   <span>/factors of 2: 1, 2; factors of 24: 1, <span>2, 3, 4, 6, 8, 12, 24/</span>

</span>Answer: A, B and D.


8 0
2 years ago
Read 2 more answers
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