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steposvetlana [31]
3 years ago
6

How much water should be added to 5 gallons of 50% acid solution to get a 20% solution?

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0

This question is based on the concept of solving an  equation. Therefore, 7.5 gallons of water would be added to 5 gallons of 50% acid solution to get a 20% solution.

Given:

5 gallons of 50% acid solution to get a 20% solution.

According to question,

Let  it be x gallons of water should be added to 5 gallons of 50% acid solution to get a 20% solution.

Now, forming the equation, we get,

 0.50 ( 5 )  =  0.20  ( x + 5 )

Simplifying the equation.

We get,

2.5 = 0.2x + 1

1.5 = 0.2 x

x = 7.5

Therefore, 7.5 gallons of water would be added to 5 gallons of 50% acid solution to get a 20% solution.

For more details, please prefer this link:

brainly.com/question/21105092

ladessa [460]3 years ago
4 0

Answer:

7.5 gallons

Step-by-step explanation:

2.5/5+x=0.2

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Answer:

The correct option is C: the isotope of iodine contains 81 neutrons.

Step-by-step explanation:

The mass (A) of the iodine isotope is given by:

A = Z + N

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For iodine Z= 53, so if A = 134 the number of neutrons is:

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I hope it helps you!

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3 years ago
a cone has a volume of 6 cubic inches. what is the volume of a cylinder that the cone fits exactly inside of
ella [17]

Answer:

= 18 cubic inches

Step-by-step explanation:

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5 0
3 years ago
Can someone please help me with this?
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That is to say 

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Think of the major arc as the larger and the minor the smaller.

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Another necessary idea is that the arc of a whole circle = 360 degrees, that is to say the major arc + minor arc = 360, giving us a second equation to solve.
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