Step-by-step explanation:
Converting all the numbers to decimals,
1) -0.5
2) 1/2 = 0.5
3) 0.7
4) -4/4 = -1
We see that order of numbers from least to greatest is -1 < -0.5 < 0.5 < 0.7
Please mark Brainliest if this helps!
ABOUT THIS FORMULA:
X2 - X1
FOR PROBLEM: (2, 1) & (0, -5)
- Y2 is -5
- Y1 is 1
- X2 is 0
- X1 is 2
ABOUT POINT SLOPE FORM:
- y - Y1 = m(x - X1)
- Y1 & X1 is a point
- m represents the slope
- This form allows you to identify the slope & the point on the line
ABOUT SLOPE INTERCEPT FORM:
- y = mx + b
- m represents the slope
- b represents the y - intercept AKA the starting point
<u>Y2 - Y1</u>
X2 - X1
<u>-5 - 1</u>
0 - 2
<u>-6</u>
-2
SIMPLIFIED: -3 because both -6 & -2 can be divided by 2.
y - Y1 = m(x - X1)
y - -1 = -3(x - 2)
y + 1 = -3x + 6
- 1 - 1
y = -3x - 5 --- SLOPE INTERCEPT FORM
I do not see y = -3x - 5 as one of your answer choices.... So, I am sorry if I am incorrect...
540 is the answer because the doubled the first number to get the second number and multiplyed that by 3 to get the third number
This is the formula for compounded interest.
P is the principal investment,
r is the rate (6%=0.06)
n is the number of times compounded per year (n=12 is monthly, n=2 is twice per year)
T is the number of years past
And A is the amount of money after t years with a rate r compounded n times per year staring at P amount
Final answer:
n is the number of times per year the interest is compounded.
Hope I helped, and sorry it took this long for you to get an answer.
Answer:
a) T test
b) Claim
because critical value is not equal to test statistic then reject null hypothesis
Step-by-step explanation:
Construction of hypothesis
H₀ : p = 75
H₁ : p ≠ 75
Here Standard deviation = 7
sample = n = 50
Average = x-bar = 78
Level of significance:
∝ = 5% = 0.05
Degree of freedom:
df = n-1
= 50 -1 = 49
Critical value :
± 1.96
a) T test
test t is used as average X mean is used
Test Statistic:
t = X₂ - X₁ / Sd /√n
= 78 - 75 / 7/√50
=3.0304
Critical region :
We take two tail T test
test statistic is in reject interval. Reject H₀
b) Claim
because critical value is not equal to test statistic then reject null hypothesis
