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Readme [11.4K]
4 years ago
13

Explain how it is possible to have sin(theta) < 0, cos(theta) < 0, and tan(theta) > 0. For which values of theta betwee

n 0 and 2????
does this happen?

Mathematics
1 answer:
Elenna [48]4 years ago
6 0

Answer:

π < ∅ < 3π/2

Step-by-step explanation:

Look at the unit circle. sin() and cos() are less than 0, so they are negative. The only place where cos() and sin() are both negative is in the third quadrant (the area I shaded in green).

tan() is the same as sin()/cos(). If you look in the third quadrant, you can divide the sin() value by the cos() at any point and it'll give you a positive number between 0 and 2 because negative divided by negative will give you a positive number.

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Please help, I do not understand this
Kryger [21]

Answer:

Step-by-step explanation:

The sin(30) = 1/2

The sin(30) = 1/2 = opposite / hypotenuse

Opposite = 7

hypotenuse = opposite / sin(30)

hypotenuse = 7 / (1/2) = 7 *2 / 1 = 14

The long side can be found using the Pythagorian Theorem.

a^2 + b^2 = c^2

a = 7

b = ?

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14^2 = 7^2 + b^2

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147 = c^2

147 = 3*7 *7

sqrt(b^2) = sqrt(3*7*7)

b = 7 sqrt(3)

6 0
3 years ago
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tatiyna

7 - 4(2w + 1) = 9w - 49 + w \\ 7 - 8w - 4 = 10w - 49 \\ 10w + 8w = 7 - 4 + 49 \\ 18w = 52 \\ w =  \frac{52}{18}  \\ w= 2.88

I hope I helped you^_^

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3 years ago
Find the value of y so that line is passing through two points
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