3x-7y = 9
Standard form is Ax+By = C
6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
Answer:
x = 6, y = 9
Step-by-step explanation:
One of the properties of a parallelogram is
The diagonals bisect each other, hence
2x = y + 3 → (1)
2y = 3x → (2)
Rearrange (1) in terms of y by subtracting 3 from both sides
y = 2x - 3 → (3)
Substitute y = 2x - 3 into (2)
2(2x - 3) = 3x ← distribute left side
4x - 6 = 3x ( add 6 to both sides )
4x = 3x + 6 ( subtract 3x from both sides )
x = 6
Substitute x = 6 into (3) for value of y
y = (2 × 6) - 3 = 12 - 3 = 9
Hence x = 6 and y = 9
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