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2 years ago

10

You deposit $600 in a savings account. The account earns 10% simple interest per year. a. What is the interest earned after 10 y

ears?

2 answers:

Rama09 [41]2 years ago

7 0

Answer:

The answer is $960

(brainliest please)

(Hope you pass :))

Step-by-step explanation:

A = P(1 + rt)

[A] is Answer

[600] is P

[10%] is r

[10] is time

Mrac [35]2 years ago

4 0

Answer:

Step-by-step explanation:

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Please solve with explanation

garik1379 [7]

Answer:

a. 49/2

b. -2/9

If I make any mistakes, I'm sorry.

4 0

1 year ago

Adult tickets are $16 and child tickets are $6. The theater sold a total of 137 tickets for a total of $1772. How many adult tic

GenaCL600 [577]

Answer:

95

Step-by-step explanation:

Let x represent the cost of adult tickets for $16

Let y represent the cost of children tickets for $6

x + y = 137...........equation 1

16x +6y = 1772............equation 2

Multiply equation 1 by 16 and equation 2 by 1

16x + 16y= 2192

-

16x + 6y = 1772

10y = 420

y= 420/10

y= 42

Substitute 42 for y in equation 1

x + y = 137

x + 42= 137

x = 137-42

x= 95

Hence 95 adult tickets were sold for $16 and 42 children tickets were sold for $6

5 0

2 years ago

Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8.<br> Simplify R - [S + T].

Mariana [72]

11-2m-(n+5+(-m)-3n+8)
11-2m-n-5-m+3n-8
Answer: -2-3m+2n

7 0

2 years ago

Read 2 more answers

How many thumbs down votes did the video get

lara31 [8.8K]

So you have the ratio of 9:2.

The video has 18 thumbs up votes with the ratio being thumbs up to thumbs down.

9 in relation to 18 is times 2 so it makes since to times 2 by 2.

Therefore the ratio would be 18:4 which means there would be 4 thumbs down.

4 0

2 years ago

At a certain university, the average attendance at basketball games has been 3125. Due to the dismal showing of the team this ye

Neporo4naja [7]

Answer:

The test statistic needed to evaluate the claim is t = -1.08.

Step-by-step explanation:

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.

At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.

This means that $\mu = 3125$

Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.

This means that $n = 9, X = 2915, s = 585$

What is the test statistic needed to evaluate the claim?

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}$

$t = -1.08$

The test statistic needed to evaluate the claim is t = -1.08.

6 0

1 year ago