Question 1)
Volume of Tank A = Sum of volume of its two parts.
So,
Volume of Tank A = 24 + 96 = 120 cubic feet
Question 2)
Volume of Tank B and Tank A is the same. So, Volume of Tank B = 120 cubic feet
One section of Tank B = 45 cubic feet
So, volume of other section of tank B = 120 - 45 = 75 cubic feet
I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.
Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.
Answer: (x^3)^2 - 3^2
Step-by-step explanation:
Answer:
Step-by-step explanation:
3
x
2
+
4
x
+
19
−
f
(
x
)
=
0
Start at one of the vertices and draw a line from there to a point on the oposite side, not ending at another vertex