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3 years ago

How do i solve this? please help.5x - 6 - 2x = 3 ( x - 2 )

Mathematics

2 answers:

MAXImum [283]3 years ago

7 0

Answer:

Infinite Solutions

Step-by-step explanation:

Distribute the 3 by multiplying it to the two terms on the right side.

5x - 6 - 2x = 3x - 6

Isolate the x value to the left and move the other terms to the right.

5x - 2x - 3x = 6 - 6

Combine all like terms.

3x - 3x = 0

0x = 0

All numbers multiplied by zero is still zero, so this equation has infinite solutions.

icang [17]3 years ago

7 0

5x-6-2x=3(x-2)
3x-6=3x-6
3x-6-3x=3x-6-3x
-6=-6
This is infinitely many solution. X can be any number

Hope this will help!!

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3 years ago

15 minus the product of 5 times the difference of p minus 6

m_a_m_a [10]

Written just as an expression it would be:

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3 years ago

Read 2 more answers

An arch is in the shape of a parabola. It has a span of 100 feet and a maximum height of 25 ft.

faltersainse [42]

Answer:

$y=-\frac{1}{100}(x-50)^2+25$

the height of the arch 10 feet from the center is 24 feet

Step-by-step explanation:

An arch is in the shape of a parabola. It has a span of 100 feet, the vertex lies at the center 50 and the maximum height of 25 ft.

Vertex at (50,25)

vertex form of the equation is

$y=a(x-h)^2+k$ , (h,k) is the center

$y=a(x-50)^2+25$

the parabola starts at (0,0) that is (x,y)

$0=a(0-50)^2+25$

subtract 25 from both sides

$-25=a(-50)^2$

$-25=a(2500)$

divide both sides by 2500

$a=-\frac{1}{100}$

$y=-\frac{1}{100}(x-50)^2+25$

the height of the arch 10 feet from the center.

center is at 50, 10 feet from the center so x=40 and x=60

$y=-\frac{1}{100}(40-50)^2+25$

y=24

the height of the arch 10 feet from the center is 24 feet

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3 years ago

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3 years ago

Please show work and thank youuu

Assoli18 [71]

Answer: $6\sqrt{3}$

======================================================

Explanation:

Method 1

We can use the pythagorean theorem to find x.

$a^2+b^2 = c^2\\\\6^2+x^2 = 12^2\\\\36+x^2 = 144\\\\x^2 = 144-36\\\\x^2 = 108\\\\x = \sqrt{108}\\\\x = \sqrt{36*3}\\\\x = \sqrt{36}*\sqrt{3}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 2

Use the sine ratio to find x. You'll need a reference sheet or the unit circle, or simply memorize that sin(60) = sqrt(3)/2

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(60^{\circ}) = \frac{x}{12}\\\\\frac{\sqrt{3}}{2} = \frac{x}{12}\\\\x = 12*\frac{\sqrt{3}}{2}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 3

Similar to the previous method, but we'll use tangent this time.

Use a reference sheet, unit circle, or memorize that tan(60) = sqrt(3)

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(60^{\circ}) = \frac{x}{6}\\\\\sqrt{3} = \frac{x}{6}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 4

This is a 30-60-90 triangle. In other words, the angles are 30 degrees, 60 degrees, and 90 degrees.

Because of this special type of triangle, we know that the long leg is exactly sqrt(3) times that of the short leg.

$\text{long leg} = (\text{short leg})*\sqrt{3}\\\\x = 6\sqrt{3}\\\\$

The short leg is always opposite the smallest angle (30 degrees).

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2 years ago