Answer:
In 1 minute, bison runs 3520 feet
In 60 minutes, the bison would run
3520*60 feet
211200 feet per hour.
These are equivalent to;
40 miles per hour since 1 mile is equivalent to 5280 feet.
The bison is faster by 10 miles per hour
Answer:
(a)
--- the catboat
--- the sloop
(b)
-- the catboat
--- the sloop
Step-by-step explanation:
Incomplete question (See attachment)
For the catboat, we have:
![Base = 9ft\\Height = 6ft](https://tex.z-dn.net/?f=Base%20%3D%209ft%5C%5CHeight%20%3D%206ft)
For the Sloop, we have:
![Base = 7 + 3 = 10ft](https://tex.z-dn.net/?f=Base%20%3D%207%20%2B%203%20%3D%2010ft)
![Height = 5ft](https://tex.z-dn.net/?f=Height%20%3D%205ft)
Solving (a): The area of both sailboats.
Since both are triangular, we use:
![Area= 0.5 * Base * Height](https://tex.z-dn.net/?f=Area%3D%200.5%20%2A%20Base%20%2A%20Height)
For the catboat
![Area= 0.5 * 9ft*6ft](https://tex.z-dn.net/?f=Area%3D%200.5%20%2A%209ft%2A6ft)
![Area= 27ft^2](https://tex.z-dn.net/?f=Area%3D%2027ft%5E2)
For the sloop
![Area = 0.5 * 10ft * 5ft](https://tex.z-dn.net/?f=Area%20%3D%200.5%20%2A%2010ft%20%2A%205ft)
![Area = 25ft](https://tex.z-dn.net/?f=Area%20%3D%2025ft)
<em>The catboat has the greater sail area because 27 > 25</em>
Solving (b): Cost of sail for each.
We have the unit price to be:
![Unit = \$1.50/ft^2](https://tex.z-dn.net/?f=Unit%20%3D%20%5C%241.50%2Fft%5E2)
So, the cost is calculated by multiplying the unit price by the total area.
So, we have:
For the catboat;
![Cost = 27ft^2 * \$1.50/ft^2](https://tex.z-dn.net/?f=Cost%20%3D%2027ft%5E2%20%2A%20%5C%241.50%2Fft%5E2)
![Cost = \$40.5](https://tex.z-dn.net/?f=Cost%20%3D%20%5C%2440.5)
For the sloop
![Cost = 25ft^2 * \$1.50/ft^2](https://tex.z-dn.net/?f=Cost%20%3D%2025ft%5E2%20%2A%20%5C%241.50%2Fft%5E2)
![Cost = \$37.5](https://tex.z-dn.net/?f=Cost%20%3D%20%5C%2437.5)
Y = -2/3x + 5....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, we flip the slope and change the sign. So our perpendicular line will have a slope of 3/2 (see how I flipped -2/3 making it -3/2....and then changed the sign, making it 3/2)
y = mx + b
slope(m) = 3/2
(8,1)....x = 8 and y = 1
now we sub and find b, the y int
1 = 3/2(8) + b
1 = 12 + b
1 - 12 = b
-11 = b
so ur perpendicular equation is : y = 3/2x - 11 <==
the angle is 138 because the area is 720