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Cerrena [4.2K]
3 years ago
10

What is the answer to this question

Mathematics
1 answer:
matrenka [14]3 years ago
7 0
The answer would be D.
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A group of retired admirals, generals, and other senior military leaders, recently published a report, "Too Fat to Fight". The r
weqwewe [10]

Answer:

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

Step-by-step explanation:

1) Data given and notation  

n=180 represent the random sample taken  

X=125 represent the number of americans between 17 to 24 that not qualify for the military

\hat p=\frac{125}{180}=0.694 estimated proportion of americans between 17 to 24 that not qualify for the military

p_o=0.75 is the value that we want to test  

\alpha=0.05 represent the significance level  

Confidence=95% or 0.95  

z would represent the statistic (variable of interest)  

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that less than 75% of Americans between the ages of 17 to 24 do not qualify for the military :  

Null hypothesis: p\geq 0.75  

Alternative hypothesis:p < 0.75  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.  

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.694 -0.75}{\sqrt{\frac{0.75(1-0.75)}{180}}}=-1.735  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of americans between 17 to 24 that not qualify for the military is significantly less than 0.75 or 75% .  

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3 years ago
How do I solve for the missing length? Please explain!! I’m struggling
REY [17]
Let call it x 
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->x=8
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Two planes are flying in opposite directions, away from each other, one with the speed of 800 km per hour and the other with the
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1640 km every hour is the answer
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PLEASE ANSWER ASAP 10 points! If a scale factor between zero and one is used, the dilation will shrink the pre-image. True or fa
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True, because if you add pi (3.14) to 0, you get the result 34.234, which is also the result of the formula which is used to shrink the dilation AND the pre-image.
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Sophie has two new fish. She feeds one fish
Zielflug [23.3K]

Step-by-step explanation:

One fish eats = 4 pellets

Second fish eats = 5 pellets

No of days one fish stays with Sophie = 72 ÷ 4 = 18 days

No of days second fish stays with Sophie = 72 ÷ 5 = 14.4 days

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3 years ago
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