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blsea [12.9K]
3 years ago
5

Hey y’all! I don’t understand this and maybe you guys could help me cuz...ya know that’s what this sight is for...haha. This is

the Solving One-Step Inequalities Practice assessment for Unit 5 lesson 9 Solving One-Step Inequalities for Connexus 6th graders.
————————————————
1. Solve the inequality 8x<48.
A) x<6 (I think it’s this one, but I’m not sure.)
B) x<40
C) x<56
D) x<13
————————————————
2. Solve the inequality 10+x>23.
A) x>2.3
B) x>13 (I think it’s this one)
C) x>33
D) x>230
————————————————
3. Solve the inequality x-14<28.
A) X<2
B) x<14
C)x<42
D)x<392
————————————————
4. Solve the inequality y/21< 3.
A) y<7
B) y<24
C) y<18
D) y<63
I have absolutely no idea how to do this problem
———————————————
5. The inequality 2 p < 18 can be used to determine how many pounds of apples are $2.00 per pound, p, you can buy will spending $18.00 or less. What is the greatest number of pounds of apples you can buy?
A) 9 pounds
B) 16 pounds
C) 20 pounds
D) 36 pounds
————————————————
6. Which values can be substituted for x to make the inequality x-4<0 true? Choose all that apply. There are 2 answers.
A) 0
B) 3 (I think this may be one of the answers)
C) 4
D) 18 (this one too)
————————————————
Please help me! I don’t understand almost all of this and the teachers aren’t much help :/ Thank you all for your time and for reading this. Have a blessed day.
Mathematics
1 answer:
kykrilka [37]3 years ago
3 0

Hello, I can give you some help w/ steps below! Hope this helps a lot :D

<em>1.</em>

8x < 48 || divide 8 on both sides of the equal sign

x < 6 || final answer, so <em>your correct</em>

<em>2</em>.

10 + x > 23 || subtract 10 on both sides of the equal sign

x > 13 || final answer, so <em>your correct</em>

<em>3.</em>

x - 14 < 28 || add 14 on both signs of the equal sign

x < 42 || final answer

<em>4.</em>

\frac{y}{21} < 3 || multiply 21 on both sides

y < 63 || final answer

<em>5.</em>

2p < 18 || divide 2 on both sides of the equal signs

p < 9 || final answer

<em>6. </em>i have no idea how to do this one, sorry!

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Answer:

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The p value is:

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Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1    H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

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The statistic to check the hypothesis is given by:

t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

Replacing the info given we got:

t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66

The degrees of freedom are given by:

df = n-1=75-1 =74

The p value since is a right tailed ted is given by:

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