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ivanzaharov [21]
3 years ago
12

3. Jim is fencing in his garden, which is in the

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0

Answer:

Step-by-step explanation: base x height

70ft

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Y = 30x + 450<br> How do I graph this?
Tanzania [10]

Answer:You start at 30 on the x axis and go up 450 1 right

Step-by-step explanation:

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4 years ago
A contractor purchases 6 dozen pairs of padded work gloves for ​$.85.68. She incorrectly calculates the unit price as ​$14.28 pe
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3 years ago
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0m0 Hello and bye also good evening
Salsk061 [2.6K]

Answer:

15/32

Step-by-step explanation:

5/8 ÷ 1 1/3

Change to an improper fraction

5/8 ÷ ( 3*1+1)/3

5/8 ÷ 4/3

Copy dot flip

5/8 * 3/4

15/32

5 0
4 years ago
Decide whether or not each equation represents a proportional relationship. A.The remaining length (L) of 120-inch rope after x
bulgar [2K]

Answer and Step-by-step explanation: An equation represents proportional relationship when dividing the quantities of the equation results in a quotient that is always the same. For example, in general:

Equation: y = mx

\frac{y}{x} = m

m is a constant value, which means is the same.

A. Equation: 120 - x = L

Equation from alternative A is NOT proportional since the division of the quantities doesn't result in a constant.

B. Equation: 1.08p = t

Dividing total cost per item's price, will always give the sales tax, which is constant. So, this equation IS proportional.

\frac{t}{p}=1.08

C. Equation: x=\frac{m}{4}

This equation is proportional because dividing marbles per how much each sister gets, always gives the number of sisters:

\frac{m}{x}=4

D. Equation: V=12s^{2}

This equation is NOT proportional because side length is squared, so it is not constant linearly.

8 0
3 years ago
Describe the solutions for the quadratic equation shown below:
PtichkaEL [24]

The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.

So, for a quadratic equation ax + bx + c = 0, the roots are

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

With a = 9, b = -6 and c = 5, the roots of our equation are

x = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 9 X 5} }{2 X 9} \\x = \frac{6 +/- \sqrt{36 - 180} }{18} \\x = \frac{6 +/- \sqrt{-144} }{18} \\x = \frac{6 +/- \sqrt{-12} }{18}\\x = \frac{6}{18} +/- i\frac{12}{18} \\x = \frac{1}{3} +/- i\frac{2}{3} \\x = \frac{1 + 2i}{3}  or \frac{1 - 2i}{3}

Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.

So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

Learn more about quadratic equations here:

brainly.com/question/18117039

5 0
3 years ago
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