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4 years ago

Y = 30x + 450 How do I graph this?

Mathematics

1 answer:

Tanzania [10]4 years ago

4 0

Answer:You start at 30 on the x axis and go up 450 1 right

Step-by-step explanation:

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Find the area of the parallelogram below.

Paul [167]

Answer:32 cm2

Step-by-step explanation:Use the formula A=BH, The 7 does not count because it isn't base or height. Use 4 times 8 which will make 32 cm2.

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3 years ago

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Given the coordinates for the function below which of the following are coordinates for its inverse

IgorLugansk [536]

Answer:

Not sure but I believe it is A

Step-by-step explanation:

7 0

3 years ago

Please help i have no idea what it means and the test is tomorrow.

Anarel [89]

Answer:

H. 2

Step-by-step explanation:

√(1 − cos² x) / sin x + √(1 − sin² x) / cos x

Use Pythagorean identity.

sin² x + cos² x = 1

So:

1 − cos² x = sin² x

and

1 − sin² x = cos² x

Substitute:

√(sin² x) / sin x + √(cos² x) / cos x

sin x / sin x + cos x / cos x

1 + 1

8 0

3 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

Factor completely 3a4y3 − 12a3y2 + 6a2y.

Firlakuza [10]

Step-by-step explanation:

$3a^4y^3-12a^3y^2+6a^2y=(3a^2y)(a^2y^2)-(3a^2y)(4ay)+(3a^2y)(2)\\\\=(3a^2y)(a^2y^2-4ay+2)$

5 0

3 years ago