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3 years ago

Solve this system of equation r+3s+t=3 2r-3s+2t=3 -r+3s-3t=1

1 answer:

5 0

Is there a picture or diagram that goes along with this. It's kinda confusing for me without the original picture. Sorry

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You want to place a towel bar that is 24 1⁄4 centimeters long in the center of a door that is 70 1⁄3 centimeters wide. How far s

Leviafan [203]

Heres Is Your Answer Below

70 1/3- 24 1/4=?

70 4/12- 24 3/12= 46 1/12

46 1/12 /2= 23 1/24

23 1/24 Would be Your Answer

Have A Great Day!

3 0

3 years ago

HELPLPOO ASAP PLEASE HELP MEE

Novosadov [1.4K]

The answer is that I think it is 5

6 0

3 years ago

Translate this sentence into an equation. 108 is the product of Carlo's age and 6.

NeTakaya

Answer:

Step-by-step explanation:

Let Carlo's age = x

Equation: 6*x = 108

6x = 108

Solution:

6x = 108

x = 108/6

x = 18

Carlo's age = 18 years

8 0

2 years ago

Read 2 more answers

In the past year, Hans watched 38 movies that he thought were very good. He watched 95 movies over the whole year. Of

Len [333]

Answer:

40%

Step-by-step explanation:

38×100=3800÷95=40

40%×95=38

8 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .

Observe the image below.

7 0

3 years ago