The formula for the area of a triangle is
1/2 b•h
Let’s plug in our values !
1/2 (30•75)
1/2 • 2,250 = ?
2,250/2 = 1,125
The area of the triangle is 1,125 cm^2
I hope I helped !
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Answer:
<h2>$5.625 (per hour)</h2>
Step-by-step explanation:
45÷8 = 5.625
What is the solution set of x2 + y2 = 26 and x − y = 6? A. {(5, -1), (-5, 1)} B. {(1, 5), (5, 1)} C. {(-1, 5), (1, -5)} D. {(5,
Rus_ich [418]
He two equations given are
x^2 + y^2 = 26
And
x - y = 6
x = y +6
Putting the value of x from the second equation to the first equation, we get
x^2 + y^2 = 26
(y + 6) ^2 + y^2 = 26
y^2 + 12y + 36 + y^2 = 26
2y^2 + 12y + 36 - 26 = 0
2y^2 + 12y + 10 = 0
y^2 + 6y + 5 = 0
y^2 + y + 5y + 5 = 0
y(y + 1) + 5 ( y + 1) = 0
(y + 1)(y + 5) = 0
Then
y + 1 = 0
y = -1
so x - y = 6
x + 1 = 6
x = 5
Or
y + 5 = 0
y = - 5
Again x = 1
So the solutions would be (-1, 5), (1 , -5). The correct option is option "C".
The answer is 2 x 10^4 or 2 to the power of 4 (4th power) where;
2 x 10 x 10 x 10 x 10
2 x 10 =20
20 x 10= 200
200 x 10 = 2000
2000 x 10 = 20 000
Expressing a number to a single digit integer times a power of 10 is also writing a number in scientific form,where the number is multiplied by 10 to nth "power". Scientific notation is also called standard index form whereby, too large or too big numbers.
In writing the scientific notation of a number it follows this form: m x 10^n ( m is multiplied to 10 to the power of n) where, m, the coefficient, is the real number and n is the exponent integer.<span><span /></span>
(4x - 3)(2x - 1) ≥ 0
First, find the zeros:
4x - 3 = 0 2x - 1 = 0
x =
x = 
Next, plot these points and choose test points on the outside and between the zeros:
←-------0------
------
------
------1------→
Lastly, plug in the test points and look for a positive result (since it is greater than 0).
Test Point 0: [4(0) - 3][2(0) - 1] = ( - )( - ) = + THIS WORKS!
Test Point
: [4(
) - 3][2(
) - 1] = ( - )( + ) = - <em>This does NOT work</em>
Test Point 1: [4(1) - 3][2(1) - 1] = ( + )( + ) = + THIS WORKS!
Answer: x ≤
or x ≥ 
Interval Notation: (-∞,
] U [
, ∞)
Graph: ←------
--------→