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3 years ago

The difference between the MDC and the LDC's

Mathematics

1 answer:

Contact [7]3 years ago

8 0

Answer: MDCs have advanced socially and economically, whereas LDCs are in the early stages of development.

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Can some one help me with this

Elza [17]

The first one
is (2,4)

5. is infinitely many solutions

because yu have tovhange the terms plces

4 0

4 years ago

Assume that the average age at which students graduate high school is 17.6. Exum (2002) asked 84 male students at a large Mid-At

disa [49]

Answer:

The null hypothesis is rejected. It can be concluded that the average age of first drink is less that 17.6 years.

Step-by-step explanation:

A one-sample z-test can be used to determine whether the average age at which students graduate high school and had their first drink is less than 17.6 years.

The hypothesis can be defined as:

H₀: The average age of first drink is 17.6 years, i.e. μ = 17.6.

Hₐ: The average age of first drink is less that 17.6 years, i.e. μ < 17.6.

The information provided is:

$n=84\\\bar x=16.54\\\sigma=2.03\\\alpha =0.05$

We are using the z-test because the population standard deviation is known and the sample size is quite large, i.e. n = 84 > 30.

Compute the test statistic value as follows:

$z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{16.54-17.6}{2.03/\sqrt{84}}=-4.79$

The test statistic value is -4.79.

Decision rule:

If the p-value of the test is less than the significance level (α) then the null hypothesis will be rejected and vice-versa.

Compute the p-value as follows:

$p-value=P(Z$

*Use a z-table for the probability.

The p-value of the test is 0.

The p-value = 0 < α = 0.05.

Thus, the null hypothesis will be rejected at 5% level of significance.

Conclusion:

As the null hypothesis is rejected it can be concluded that the average age of first drink is less that 17.6 years.

6 0

4 years ago

Which of the following are exterior angles? Check all that apply

Eduardwww [97]

Angles 3 ,2 ,6 , and 5 are exterior angles

7 0

3 years ago

Simplify the expression by using a double-angle formula 1-2sin^2(3theta)

NeTakaya

We know that:

$\cos(2x)=1-2\sin^2(x)$

Here $x=3\theta$ so:

$1-2\sin^2(3\theta)=\cos(2\cdot3\theta)=\cos(6\theta)$

5 0

4 years ago

The ratio of the perimeters of two similar triangles is 4:7. What is the area of each of these triangles if the sum of their are

Mashcka [7]

Answer:

The area of triangles are 16 cm^2 and 49 cm^2

Step-by-step explanation:

we know that

If two figures are similar, the ratio of its perimeters is equal to the scale factor and the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the smaller triangle in square centimeters

y ----> the area of the larger triangle in square centimeters

we know that

$z=\frac{4}{7}$

$\frac{x}{y}=z^2$

$\frac{x}{y}=(\frac{4}{7})^2$

$\frac{x}{y}=\frac{16}{49}$

$x=\frac{16}{49}y$ -----> equation A

$x+y=65$ ----> equation B

solve the system by substitution

substitute equation A in equation B

$\frac{16}{49}y+y=65$

solve for y

$\frac{65}{49}y=65$

$y=49\ cm^2$

Find the value of x

$x=\frac{16}{49}(49)$

$x=16\ cm^2$

therefore

The area of triangles are 16 cm^2 and 49 cm^2

3 0

4 years ago

Read 2 more answers

The difference between the MDC and the LDC's​

The difference between the MDC and the LDC's