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sergey [27]
2 years ago
5

The difference between the MDC and the LDC's​

Mathematics
1 answer:
Contact [7]2 years ago
8 0

Answer: MDCs have advanced socially and economically, whereas LDCs are in the early stages of development.

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Find the mean of the weights.<br> 0.8158 0.8194 0.8164 0.8175 0.7911 0.8144 0.8123
denis23 [38]

Answer:

0.81241

if i'm wrong i'm rlly rlly sorry!!

4 0
3 years ago
When you receive a loan to make a purchase, you often must make a down payment in cash. The amount of the loan is the purchase c
emmainna [20.7K]
Summarizing the problem, there are three terms that you have to deal with: purchasing cost, down payment and loan. So, you would expect that the answer would contain these quantities. Among them, the unknown is the purchasing cost, therefore, we denote this as x. 

<span>Based on the statement, "The amount of the loan is the purchase cost minus the down payment", we can formulate an equation for this. 

Amount of Loan = x - Down payment

This will be our working equation. Moving on, the down payment was mentioned to be equal to </span>$1500. The lean received is equal to <span>$2600. Substituting these values to the working equation, we can now determine the value of x.

2600 = x - 1500

Solving for x by transposing it to one side,

x = 2600-1500
x = $1,100

Therefore, the purchasing cost of the car is $1,100.</span>
6 0
3 years ago
A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the
Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= \pi r^2h

According to the problem,

\pi r^2 h=25

\Rightarrow h=\frac{25}{\pi r^2}

The surface area of the base of the can is = \pi r^2

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× \pi r^2)

The lateral surface area of the can is = 2\pi rh

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× 2\pi rh)

                                                 =\$2.5 \pi r h

Total cost of metal is C= 2.00 \pi r^2+2.5 \pi r h

Putting h=\frac{25}{\pi r^2}

\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}

\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}

Differentiating with respect to r

C'=4\pi r- \frac{62.5}{ r^2}

Again differentiating with respect to r

C''=4\pi + \frac{125}{ r^3}

To find the minimize cost, we set C'=0

4\pi r- \frac{62.5}{ r^2}=0

\Rightarrow 4\pi r=\frac{62.5}{ r^2}

\Rightarrow  r^3=\frac{62.5}{ 4\pi}

⇒r=1.71

Now,

\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0

When r=1.71 cm, the metal cost will be minimum.

Therefore,

h=\frac{25}{\pi\times 1.71^2}

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0
3 years ago
Which expression is equal to 2X^2+7<br> (Simplify)
almond37 [142]

This expression cannot be simplified any further.

5 0
3 years ago
$46 shoes, 2.9% tax what is the total cost
Amanda [17]
\$46\times (1+\frac{2,9}{100})=\$46\times1,029=\$47,334
8 0
3 years ago
Read 2 more answers
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