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joja [24]
2 years ago
10

Derivative using direct definition of derivative 2-x/2+x

Mathematics
1 answer:
Daniel [21]2 years ago
3 0

Let <em>f(x)</em> = (2 - <em>x</em>)/(2 + <em>x</em>). By definition of the derivative,

\displaystyle f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}h

\displaystyle f'(x)=\lim_{h\to0}\frac{\frac{2-(x+h)}{2+(x+h)}-\frac{2-x}{2+x}}h

\displaystyle f'(x)=\lim_{h\to0}\frac{\frac{(2-x-h)(2+x)-(2-x)(2+x+h)}{(2+x+h)(2+x)}}h

\displaystyle f'(x)=\lim_{h\to0}\frac{-4h}{h(2+x+h)(2+x)}

\displaystyle f'(x)=-4\lim_{h\to0}\frac1{(2+x+h)(2+x)}=\boxed{-\frac4{(2+x)^2}}

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Least to greatest 0.95 0.61 5/8
lara31 [8.8K]

Answer: 0.61, 5/8, 0.95

Step-by-step explanation:

4 0
3 years ago
-5 5/6 + (-8 4/5)= what show the work
djverab [1.8K]

Answer:

-13 2/3

Step-by-step explanation:

-5 5/6               5x6= 30 4x5= 20

+                                20/30= 2/3

-8 4/5

-----------      -5 + -8 = -13

-13  2/3

hope this helps

6 0
3 years ago
help with number 2 please i have no idea how to do this. it would be very helpful if you can show the steps
zloy xaker [14]
So in this case, we have to replace the known value.
y=3
y=-2x+3

3=-2x+3

Then we leave our unknown value alone.
\frac{3-3}{2}= x

In this case, our x value would be 0.

We check it...
3=-2(0)+3
3=0+3
3=3

So y=3 x=0

For the second one we have...
y=3x+2
y=-3x-4

For this we substitute the y in any of the equation...
3x+2=-3x-4

We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2

Then we solve
6x=-6

Then we leave the unknown value alone.
x=\frac{-6}{6}

Then solve for x.
x= -1

Then for our y value we return to one of the original equations and substitute the x value.
y=3x+2
y=3(-1)+2
y=-3+2
y=-1

y=-3x-4
y=-3(-1)-4
y=3-4
y=-1

So in this case we got that x= -1 and y= -1
4 0
3 years ago
Solve for m 13x - 10<br> M<br> N<br> 7x - 10
lisov135 [29]

Answer:

x = 10

Step-by-step explanation:

Given:

Arc LM = 13x - 10

Arc MN = 7x - 10

Required:

Solve for x

Solution:

Recall: half a circle = 180°

Therefore,

Arc LM + Arc MN = 180°

13x - 10 + 7x - 10 = 180

Add like terms

20x - 20 = 180

20x - 20 + 20 = 180 + 20

20x = 200

20x/20 = 200/20

x = 10

7 0
3 years ago
Russ is constructing the inscribed circle for △ABC . He has already used his compass and straightedge to complete the part of th
NemiM [27]
The answer is C.

Place the point of the compass on point C and draw an arc that intersects AC¯¯¯¯¯  and BC¯¯¯¯¯ .


7 0
3 years ago
Read 2 more answers
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