Answer:
3) 124
Step-by-step explanation:
a1 = 10
a2 = a1+6 = 10+6 = 16
a3 = a2+6 = a1+6+6 = a1 + 2×6 = 22
a4 = a3+6 = a2+6+6 = a1+6+6+6 = a1 + 3×6 = 28
...
=>
an = an-1 + 6 = a1 + 6(n-1)
=>
a20 = a1 + 6(20-1) = 10 + 6×19 = 10+114 = 124
Answer:
A.Y
B.X
C.They become opposite
Step-by-step explanation: A. When you reflect the x - axis you don't change the y - axis B: Same as A C: You multiply them both by -1 basicly
Answer:
C. 13
Step-by-step explanation:
from on online source, the question should be placed as thus:
Of the following integers, which is the closest approximation to (√2 + √5)^2 ?
A. 7
B. 10
C. 13
D. 15
E. 17
This is known as Algebraic expression. So we have to expand to simplify further
using this identity th (a+b)^2 = a^2 + b^2 +2ab
(√2 + √5)^2 =
(√2 + √5)(√2 + √5)
................Expansion of the above
2 + 5 + 2√10
~ 2 +5 + 2(3)
C. 13
First of all, you add 1/3 and 4/5, so you get:
To add 2 fractions, they need to have the same denominator. Since 3 and 5 don't have a common factor, so you multiply 1/3 by 5, and 4/5 by 3, so you get:
Now, the two fractions got the same denominator, and you can add them by adding the numerators over the same denominator. (You don't add denominators in addition) so you get:
That's the sum of 1/3 + 4/5.
Now, they want the sum of the 2 fractions 7 times. So you multiply 17/15 by 7. And as you know, 7 = 7/1. So you get:
In multiplication no need to have the same denominator. You multiply nominators by nominators and denominators by denominators. So you get:
Since 119 and 15 don't have a common factor, so they can't be simplified.
So, the answer is 119/15.
Hope this Helps! :D
Answer:
108 student tickets, and 176 adult tickets were sold
Step-by-step explanation:
Adult ticket $8 Call the number of adult tickets sold "a"
Student ticket $5 Call the number of student tickets sold "s"
Since we are talking about TWO consecutive days of sold out seats, the total number of seats sold were 2* 142 = 284
Then we create two different equations with the information given:
a + s = 284
8 * a + 5 * s = 1948
we can solve for s in the first equation as follows: s = 284 - a
and use it in the second equation
8 a + 5 (284 - a) = 1948
8 a + 1420 - 5 a = 1948
combining
3 a = 528
a = 528/3
a = 176
we find the number of student tickets using this answer in the substitution equation we used:
s - 284 - 176 = 108
Therefore 108 student tickets, and 176 adult tickets were sold.