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Hunter-Best [27]
3 years ago
12

Through a point not on a line, one and only one liParallel lines are cut by a transversal such that the alternate interior angle

s have measures of 3x + 17 and x + 53 degrees. The value of x is
A 9
B 18
C 35
D 71
Mathematics
1 answer:
galina1969 [7]3 years ago
5 0
<span>Parallel lines are cut by a transversal such that the alternate interior angles have measures of 3x + 17 and x + 53 degrees. The value of x is 
18 </span>
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$600 7) Nika puts 42 beads in each necklace. Which is the best way to use rounding numbers to estimate the number of beads Nika
kkurt [141]

Answer:

20 X 40 = 800 (split into 2 fourths) = 40

Step-by-step explanation

20 x 40 = 800;

For 2 necklaces she can split 800 into fourths.

800 - 40 = 80. (1 fourth)

80 - 40 = 40 (2 fourths)

40 - 40 = 0 (3 fourths)

She could split 800 into 2 fourths to get a number more than 0 and less then 42.

The best estimate of rounding 42 is 40. Because 40 is closer to 42.

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3 years ago
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emmasim [6.3K]

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-4 equals p=2 and a and R are at point Y downwards.

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2 years ago
Which of the following are accurate descriptions of the description below? Choose all answers that apply:
Savatey [412]

Answer:

C. None of The Above

Step-by-step explanation:

The peak is at 2 years, not 4. And there is no gap.

4 0
3 years ago
Does anyone know the answer?
laila [671]

Answer:

a. θ = 30°

b. μ = √3 / 15 ≈ 0.115

Step-by-step explanation:

Draw a free body diagram for each scenario (see attached figure).  The body has four forces acting on it:

  • Weight pulling down
  • Normal force perpendicular to the incline
  • Applied force parallel up the incline
  • Friction force parallel to the incline

Remember that friction opposes the direction of motion.  So when the body is sliding up, friction points down the incline.  And when the body is sliding down, friction points up the incline.

Now apply Newton's second law to each scenario, first in the normal direction, then in the parallel direction.

For sliding up, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of the forces parallel to the incline:

∑F = ma

P₁ − f − mg sin θ = 0

P₁ − Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₁ − mgμ cos θ − mg sin θ = 0

Now for sliding down, sum of the forces normal to the incline:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

And sum of the forces parallel to the incline:

∑F = ma

P₂ + f − mg sin θ = 0

P₂ + Nμ − mg sin θ = 0

Substituting the expression for normal force:

P₂ + mgμ cos θ − mg sin θ = 0

We know that P₁ = 6 kg.wt, P₂ = 4 kg.wt, and mg = 10 kg.wt.

So we have two equations and two unknowns (μ and θ):

P₁ − mgμ cos θ − mg sin θ = 0

P₂ + mgμ cos θ − mg sin θ = 0

Let's start by adding the equations together:

P₁ + P₂ − 2 mg sin θ = 0

P₁ + P₂ = 2 mg sin θ

sin θ = (P₁ + P₂) / (2 mg)

Plugging in the values:

sin θ = (6 + 4) / (2 × 10)

sin θ = 1/2

θ = 30°

Now we can plug this into either equation and find μ.

P₁ − mgμ cos θ − mg sin θ = 0

6 − (10 cos 30°) μ − 10 sin 30° = 0

6 − 5√3 μ − 5 = 0

1 = 5√3 μ

μ = √3 / 15

μ ≈ 0.115

6 0
3 years ago
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