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alexira [117]
3 years ago
11

PLEASE HELP I WILL GIVE BRAINLIEST TO THE FIRST PERSON THAT ANSWER PLEASE

Mathematics
1 answer:
user100 [1]3 years ago
8 0

Answer:

a) x = k \times \frac{1}{y^2} \ , \ where \ k \ is \ a \ constant\\\\b) x = 3, \ when\  y\  =\  10\\\\c) y = 10, \ when \ x = 3

Step-by-step explanation:

a)

x \ \alpha  \ \frac{1}{y^2}\\\\x = k \times \frac{1}{y^2}\\\\                [ \ where \ k \ is \ a \ constant \ ]

<em><u>Find k.</u></em>

Given x = 12, y = 5,

12 = k \times \frac{1}{5^2}\\\\k = 12 \times 25 = 300

b)

<em><u>Find x.</u></em>

Given y = 10

We have k = 300

x = k \times \frac{1}{y^2}\\x = 300 \times \frac{1}{10^2} \\\\x= \frac{300}{100} = 3

c)

<u><em>Find y</em></u>

Given x = 3

We have k = 300

x = k \times \frac{1}{y^2}\\\\3 = 300 \times \frac{1}{y^2}\\\\\frac{1}{y^2} = \frac{3}{300}\\\\\frac{1}{y^2} = \frac{1}{100}\\\\y^2 = 100\\\\y = \sqrt{100}  = 10

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