Question

(2a^x + b^x)^2 i need help ASAP

Answer 1

Answer:

4$a^{2x}$ + 4$a^{x}$$b^{x}$ + $b^{2x}$

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

Given

(2$a^{x}$ + $b^{x}$ ) = (2$a^{x}$ + $b^{x}$ )(2$a^{x}$ + $b^{x}$ )

Each term in the second factor is multiplied by each term in the first factor, that is

2$a^{x}$ (2$a^{x}$ + $b^{x}$ ) + $b^{x}$ (2$a^{x}$ + $b^{x}$ ) ← distribute both parenthesis

= 4$a^{2x}$ +2 $a^{x}$$b^{x}$ + 2$a^{x}$$b^{x}$ + $b^{2x}$ ← collect like terms

= 4$a^{2x}$ + 4$a^{x}$$b^{x}$ + $b^{2x}$