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vesna_86 [32]
2 years ago
15

Is this correct ? if not what’s the correct answer?

Mathematics
1 answer:
Snezhnost [94]2 years ago
4 0

Answer:

yes

Step-by-step explanation:

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A new car valued at 24,000 depreciates at 9% per year. What is the value of the car one year after purchase?
Artist 52 [7]

Answer:

$21840

Step-by-step explanation:

24000*0.91=21840

8 0
2 years ago
Select the equation of the line parallel to 2x + 6y = -4 the equation and that passes through the point (3, -3) .
vagabundo [1.1K]

Answer:

\displaystyle x + 3y = -6

Step-by-step explanation:

Plugging these coordinates into this equation will give you this:

3 - 9 = −6 ☑

* This is a genuine statement.

I am joyous to assist you anytime.

4 0
3 years ago
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
How many liters of water must Sharon add to 2 liters of a sugar and water solution that is 36% sugar to create a solution that i
Dahasolnce [82]

The amount of sugar x in the starting solution contributes to a 36% concentration, so we have

\dfrac x2=0.36\implies x=0.64

units of sugar in the solution.

Into this solution, Sharon wants to pour y liters of water to obtain a smaller concentration of sugar in the overall solution:

\dfrac{0.64}{2+y}=0.12\implies\dfrac{16}3=2+y\implies y=\dfrac{10}3\approx3.33

So Sharon needs to add \dfrac{10}3 liters of water to the solution to get the desired concentration.

3 0
3 years ago
What is the volume of a rectangular prism which is 4.25 inches length, 3.75 inches width and 10 ½ inches height? You must show y
pav-90 [236]

The volume would be 167.344 cubic inches because 4.25 times 3.75 times 10.5 or 10 1/2 is 167.34375 but you would round so your answer would be 167.344 cubic inches.

8 0
3 years ago
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