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vesna_86 [32]
2 years ago
15

Is this correct ? if not what’s the correct answer?

Mathematics
1 answer:
Snezhnost [94]2 years ago
4 0

Answer:

yes

Step-by-step explanation:

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If y varies directly as x and y = 42 when x = 6, find the equation that gives the relationship between x and y.
Troyanec [42]

Answer:

B

Step-by-step explanation:

since K is constant ( the same for every point) we can find k when given any point by dividing the y-coordinate by the x-coordinate.

6 0
3 years ago
The ratio of collectible coins Juanita owns to coins that Elia owns is 3:1. Elia has 32 coins. How will the ratio of Juanita’s c
yaroslaw [1]
Hi there Maebe, since the ratio is 3:1 your answer is 96.

The ratio 3:1 is just saying Juanita has 3 times whatever Elita has. So, Elita’s 32 times 3 equals 96. :) I hope I’ve helped you. Please give me feedback if you need more help understanding!
7 0
3 years ago
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
3 years ago
Mike is reading a map with a scale of 1 in. = 35 mi. On the map, the
Umnica [9.8K]

Answer:

Actual distance represented by 5.5 inch of map distance is

192.5 miles

Step-by-step explanation:

Given,

The scale of map -

1 inch on map is equal to 35 miles.

Distance measured by mike on map is equal to 5.5 inch

Actual distance represented by 5.5 inch of map distance is

= 5.5 * 35 = 192.5 miles

8 0
3 years ago
1 A square is a rectangle.
irinina [24]
1.sometimes
2. always
3.never
3 0
3 years ago
Read 2 more answers
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