1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
notsponge [240]
3 years ago
5

A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an

d 952 as non fraudulent (920 correctly so). Construct the classification matrix and calculate the error rate.Suppose that this routine has an adjustable cutoff (threshold) mechanism by which you can alter the proportion of records classified as fraudulent. Describe how moving the cutoff up or down would affect the following:a. The classification error rate for records that are truly fraudulentb. The classification error rate for records that are truly non fraudulent

Mathematics
1 answer:
MrMuchimi3 years ago
3 0

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

You might be interested in
Only 17 plz rlly need help plz bro
Airida [17]
The question GIVES us an equation: 

V₀ = √(v² - 64h) .

It TELLS us that v should be 100 ft/sec and h is 150 ft.
All we have to do is plug the numbers into the equation,
and then do the arithmetic to find V₀.
There's not even any Physics to do.  Only arithmetic.

V₀ = √(v² - 64h)

v = 100 
h = 150

V₀ = √(100² - 64·150)

V₀ = √(10,000 - 9,600)

V₀ = √400

V₀ = 20 ft per sec .
 
4 0
4 years ago
The dot plot below shows 6 data points with a mean of 16.
lianna [129]

Answer:I think its C

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If 4^(3x-2)=4^(x+1), then x=
chubhunter [2.5K]

Answer:

x = 3 /2

x=1.5

Step-by-step explanation:

7 0
3 years ago
Please please help me
Soloha48 [4]
The answer is D, they are independent because they intersect at one point.
7 0
4 years ago
What is the answer 6(a - b + 4) please help show how you solved ​
Hatshy [7]

Answer:

69420

Step-by-step explanation:

i took quiz

7 0
3 years ago
Read 2 more answers
Other questions:
  • A rectangular prism has a width of 5 cm a height of 8cm and a depth of 5cm. What is the volume of the prism
    10·1 answer
  • A balloon flying at 3000 feet above the ocean measures the angles of depression of each end of an island directly in front of th
    11·1 answer
  • You are taking a test in science. For every 3 questions, you have 5 minutes.
    5·1 answer
  • Round 5.830951895 I WILL MARK U AS BRAINLIEST ;)
    13·2 answers
  • Find the amount of water the tank can hold to the nearest gallon
    15·1 answer
  • Write the equation of the line parallel to 5x + y = -2 that goes through the point (2, -3).​
    12·1 answer
  • We are two numbers <br> Our median is 3 <br> Our minimum is 2, What numbers are we?
    5·2 answers
  • **URGENT!!! 30 POINTS &amp; BRAINLIEST
    15·1 answer
  • PLS HELP 15 POINTS AND I'LL GIVE BRAINLIEST! What can you notice about the circumcenter, incenter, orthocenter, and centroid of
    7·1 answer
  • Victoria has a cow. The cow’s tail is 3 inches long. The cow’s tail grows by 5 inches every 6 months. What will the tail’s lengt
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!