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Dahasolnce [82]

3 years ago

13

IQ scores for adults aged 20 to 34 years are normally distributed according to N (110,25). Use the empirical rule to answer the

following: Approximately what percent of people in this group have scores below 110?

1 answer:

xxTIMURxx [149]3 years ago

6 0

Since the mean of the distribution is 110, and the distribution is normal, then 50% of the the people will have scores below 110.

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The height of a cylinder is 5 centimeters. The diameter of the base of the cylinder is 16 centimeters. Find the lateral surface

soldier1979 [14.2K]

Answer:

Lateral surface area of the cylinder = $251.2 cm^2$

Step-by-step explanation:

Lateral surface area of he cylinder = $2*\pi*r*h$ i.e area of side surface.

$Height(h) = 5 cm$

$Diameter = 16 cm$

$radius(r)= 16/2= 8 cm$

Lateral surface area of the cylinder = $2*\pi *8*5$

$\pi =\frac{22}{7}=3.14$

L.S.A= $2*3.14*8*5$

L.S.A= $251.2 cm^2$

The lateral surface area of the cylinder with radius 8 cm and height 5 cm is $251.2 cm^2$

6 0

3 years ago

Calculate the area of the shaded region.

Nostrana [21]

Let $A$ be the area of the sector in the larger circle (radius 12 cm) whose central angle is subtended by the labeled arc with measure 45 deg, and let $a$ be the area of the sector in the smaller circle (radius 8 cm) with the same central angle. The area you want is $A-a$ .

We have

$\dfrac A{\pi(12\,\mathrm{cm})^2}=\dfrac{45^\circ}{360^\circ}\implies A=18\pi\,\mathrm{cm}^2$

$\dfrac a{\pi(8\,\mathrm{cm})^2}=\dfrac{45^\circ}{360^\circ}\implies a=8\pi\,\mathrm{cm}^2$

So the area of the shaded region is $18\pi-8\pi=10\pi$ .

7 0

3 years ago

Trevor surveyed attendees at a comic book convention about the distance they lives from the convention center in the top of tick

attashe74 [19]

Answer:137

Im not completely sure though!

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

HELP ME OUT PLEASE I RLLY NEED IT ASAP. ):

LenaWriter [7]

(a) Slope is rise over run, or change in y over change in x.

1 -> 3 ( $\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{4 - -8}{-1 - -5} = \frac{4 + 8}{-1 +5}= \frac{12}{4} =\frac{12}{4}$ )

2 -> 3 ( $\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{1 - 7}{0 - 2} = \frac{-6}{- 2} =\frac{6}{2}$ )

3 -> -1/3 ( $\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{-7 - -3}{6 - -6}= \frac{-7+3}{6+6}=\frac{-4}{12}=-\frac{1}{3}$ )

(b) If a line is parallel, the slopes will be the same. If they are perpendicular, the slopes will be are negative reciprocals of one another. If they are neither, then their slopes don't match up in any way.

1 & 2 -> Parallel

1 & 3 -> Perpendicular

2 & 3 -> Perpendicular

Note - Since 1 & 2 are parallel, then both 1 and 2 will be perpendicular to 3!

Have a nice day!

If this is not what you are looking for - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

5 0

3 years ago

Read 2 more answers

Which variable will you choose to eliminate? How?

Inga [223]

Answer:

Variable elimination

8x+3y=-7
3y=-8x-7
y=-8/3x-7/3

Now plug it into y
7x-16/3x-14/3=-3
5/3x-14/3=-3
5/3x=5/3
x=1

4 0

3 years ago