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polet [3.4K]
3 years ago
6

Write a numerical expression for the word expression. 100 decreased by 77

Mathematics
1 answer:
Goryan [66]3 years ago
3 0

Answer:

100-77

Step-by-step explanation:

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Find the diameter of a circle whose circumference is 74cm
jenyasd209 [6]
  • <em>Answer:</em>

<em>≈ 24 cm</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>c = 2πr  } => c = πd => d = c/π</em>

<em>2r = d</em>

<em>replace c ; π</em>

<em>π  =3.14</em>

<em>d = 74cm/3.14</em>

<em>= 23.5668</em>

<em>≈ 24 cm</em>

<em>Good luck !</em>

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3 years ago
Sooooo bored ask me anything even if it´s not on the list
serg [7]

Answer:

What oets do you like? whats your height u noob

Step-by-step explanation:

6 0
3 years ago
What are the intercepts of 3x – 2y = 12. put answers in as an orders pair<br> (PLEASE HELP)
slega [8]

Answer:

x int (4,0)

y int (0, -6)

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A cylindrical well has a radius of 8 feet and a height of 13 feet what is the volume of the well use 3.14 for pie round your ans
vitfil [10]
To find the volume of a cylinder, you use this formula:
V = \pir^{2}h

Plug in your numbers,
V = (3.14 * 8^{2}) * 13

Exponents:
V = (3.14 * 64) * 13

Parentheses:
V = 200.96 * 13

Multiply:
V = 2612.48ft^{2}
8 0
3 years ago
Find the equation of the parabola with focus (5, 1) and directrix y = -1.
Mumz [18]
Check the picture below.

since the focus point is above the directrix, that simply means the parabola is a vertical one, and therefore the square variable is the "x".

keeping in mind that, there's a distance "p" from the vertex to either the focus point or the directrix, that puts the vertex half-way between those fellows, in this case at 0, right between 1 and -1, as you see in the picture, and the parabola looks like so.

since the parabola is opening upwards, the value for "p" is positive, thus

\bf \textit{parabola vertex form with focus point distance}&#10;\\\\&#10;\begin{array}{llll}&#10;4p(x- h)=(y- k)^2&#10;\\\\&#10;\boxed{4p(y- k)=(x- h)^2}&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ( h, k)\\\\&#10; p=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;h=5\\&#10;k=0\\&#10;p=1&#10;\end{cases}\implies 4(1)(y-0)=(x-5)^2&#10;\\\\\\&#10;4y=(x-5)^2\implies  y=\cfrac{1}{4}(x-5)^2

8 0
3 years ago
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