Apply the product rule to
7
11
7
11
.
(
2
7
)
2
⋅
7
2
11
2
(
2
7
)
2
⋅
7
2
11
2
Raise
7
7
to the power of
2
2
.
(
2
7
)
2
⋅
49
11
2
(
2
7
)
2
⋅
49
11
2
Raise
11
11
to the power of
2
2
.
(
2
7
)
2
⋅
49
121
(
2
7
)
2
⋅
49
121
Multiply
2
(
49
121
)
2
(
49
121
)
.
Tap for more steps...
(
2
7
)
98
121
(
2
7
)
98
121
Apply the product rule to
2
7
2
7
.
2
98
121
7
98
121
2
98
121
7
98
121
The result can be shown in multiple forms.
Exact Form:
2
98
121
7
98
121
2
98
121
7
98
121
Decimal Form:
0.36253492
…
0.36253492
…
(
2
7
)
2
⋅
(
7
1
1
)
2
(
2
7
)
2
⋅
(
7
1
1
)
2
<h3>
Answer: Choice A</h3>
The area of square T is equal to the sum of the areas of square R and square S.
=======================================================
Explanation:
Recall that the pythagorean theorem says
a^2+b^2 = c^2
Visually this means if we had a square with side length 'a', then its area is a^2. The same goes for a square with side length b. Its area is b^2
So a^2+b^2 is the sum of those square areas. It being equal to c^2 tells us that adding the smaller square areas lead to the largest square area.
So that's why the areas of squares R and S add up to the area of square T.
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An example:
Let's say...
- square R has side length 3
- square S has side length 4
- square T has side length 5
note how 3^2+4^2 = 9+16 = 25 and how 5^2 = 25. This shows 3^2+4^2 = 5^2
i believe you have to do 200 devided by 5 im not sure.
Given an isosceles triangle with a leg length of 24 inches and a perimeter of 82 inches.
This means that the length of the other side is 82 - 2(24) = 82 - 48 = 34 inches
Given that the triangle is rotated about a line that passes through points B and D, point D being the midpoint of line AC.
Then, the resulting <span>three-dimensional figure will be a cone with a base radius equal to the length of line AD (i.e. half of the length of line AC being the other side of the isosceles triangle).
The base radius of the resulting cone is 1/2 (34) = 17 inches</span>.
Therefore, the resulting <span>three-dimensional figure is a cone with base radius of 17 in</span>ches.