Answer:
Reflection over the x- axis
Step-by-step explanation:
The correct question is
Use the given information to find the exact value of the expression. sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
we know that
sin(α − β<span>) = </span>sin α cos β − cos α sin β
α lies in quadrant II
so
cos α is negative
sin α is positive
β lies in quadrant I
so
cos β is positive
sin β is positive
step 1
find sin β
cos β=15/17
sin² β+cos² β=1-----------> sin² β=1-cos² β----> sin² β=1-(15/17)²
sin² β=1-225/289-----> 64/289
sin β=8/17
step 2
find cos α
sin α = 21/29
cos² α + sin² α=1----> cos² α=1-sin² α---> cos² α=1-(21/29)²---> 1-441/841
cos² α=400/841------> cos α=-20/29 (remember cos α is negative)
step 3
find sin(α − β)
sin α = 21/29 cos α=-20/29
sin β=8/17 cos β=15/17
sin(α − β) = [21/29]*[15/17] − [-20/29*]*[8/17]
sin(α − β) = [315/493] − [-160/493]
sin(α − β) = 475/493
the answer is
sin(α − β) = 475/493
Part A: Find the area of the circle of spilled milk as a function of time, or A[r(t)].
A(r(t)) = A(4t) = π(4t)^2 = 16πt^2
A[r(t)] = 16πt^2
Part B: How large is the area of spilled milk after 4 minutes? You may use 3.14 to approximate π in this problem.
After 4 minutes, A = 16(3.14)(4)^2 = 803.84 cubic meters.
The correct answer is A. when solving these graphs the number in the x-axis is always flipped ex: -4 would be +4, and +4 would be -4
Answer:
area = 88 mi²
Step-by-step explanation:
all vertical dimensions = 8/2 = 4 mi
area = (4 x 11.9) +(4 x 6.1) + (4 x 4) = 88 mi²
