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Lesechka [4]
3 years ago
5

Uihhijljgkhjhcgjhkgv

Computers and Technology
2 answers:
Anvisha [2.4K]3 years ago
7 0

Answer:

HTML is system for tagging text files to achieve fonts, colour, graphics and hyperlink effects.

Full form- Hyper text Mark up Language

OleMash [197]3 years ago
4 0

Answer:

AVNAOWVN;AKBVAOJNBA

Explanation:

You might be interested in
Instructions
e-lub [12.9K]

Answer:

See explaination

Explanation:

dateType.h

#ifndef dateType_H

#define dateType_H

class dateType

{

public:

void setDate(int month, int day, int year);

//Function to set the date.

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day;

// dYear = year

int getDay() const;

//Function to return the day.

//Postcondition: The value of dDay is returned.

int getMonth() const;

//Function to return the month.

//Postcondition: The value of dMonth is returned.

int getYear() const;

//Function to return the year.

//Postcondition: The value of dYear is returned.

void printDate() const;

//Function to output the date in the form mm-dd-yyyy.

void isLeapYear() const;

dateType(int month = 1, int day = 1, int year = 1900);

//Constructor to set the date

//The member variables dMonth, dDay, and dYear are set

//according to the parameters.

//Postcondition: dMonth = month; dDay = day; dYear = year;

// If no values are specified, the default

// values are used to initialize the member

// variables.

private:

int dMonth; //variable to store the month

int dDay; //variable to store the day

int dYear; //variable to store the year

};

#endif

dateType.cpp

#include <iostream>

#include "dateType.h"

using namespace std;

void dateType::setDate(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

int dateType::getDay() const

{

return dDay;

}

int dateType::getMonth() const

{

return dMonth;

}

int dateType::getYear() const

{

return dYear;

}

void dateType::printDate() const

{

cout << dMonth << "-" << dDay << "-" << dYear;

}

void dateType::isLeapYear() const

{

if ( dYear%400 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%100 == 0)

cout<<endl<<dYear<< " is leap year.\n";

else if ( dYear%4 == 0 )

cout<<endl<<dYear<< " is leap year.\n";

else

cout<<endl<<dYear<< " is not leap year.\n";

}

//Constructor with parameters

dateType::dateType(int month, int day, int year)

{

// Checking month is valid

while(month<1 || month>12)

{

cout << "Enterd month "<<month<< " is wrong"<<endl;

cout << "Enter correct month"<<endl;

cin>>month;

}

dMonth = month;

// Checking date is valid

while(day<1 || day>31)

{

cout << "Enterd date "<<day<<" is wrong"<<endl;

cout<<"Enter correct date"<<endl;

cin>>day;

}

dDay = day;

int count_digits = 0;

int flag=0;

int year1;

// Counting number of digits in year

while(flag==0)

{

year1=year;

count_digits=0;

while (year) {

year /= 10;

count_digits++;

}

if(count_digits != 4)

{

cout << "Enterd year "<<year1<<" is wrong"<<endl;

cout<<"Enter correct year"<<endl;

cin>>year;

flag=0;

}

else

flag=1;

}

dYear = year1;

}

main.cpp

#include<iostream>

#include "dateType.h"

using namespace std;

int main()

{

dateType *dt1=new dateType();

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

dateType *dt2=new dateType(11,14,2019);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt2->setDate(13,32,2016);

cout<<"Date is "<<endl;

dt2->printDate();

cout<<endl;

dt2->isLeapYear();

cout<<endl;

dt1->setDate(10,10,198);

cout<<"Date is "<<endl;

dt1->printDate();

cout<<endl;

dt1->isLeapYear();

cout<<endl;

system("pause");

return 0;

}

6 0
3 years ago
How can I cancel my subscription I try to go to my account setting and the only thing that pops up is terms of use and change co
Sati [7]

If the only trying that appears is terms of use and change country, that means you are a free user and not a paying subscriber.

So there is no actual subscription to cancel.

If you were a paying subscriber, there would be a cancel subscription option within your account settings.

8 0
2 years ago
To make a duplicate of text, image,chart,graphs etc.​
Veronika [31]

Explanation:

You can change the formatting of the rest of the text ( bold, italics, font color or sixe, ect)

5 0
3 years ago
if image size and resolution are the same, which file format, .jpg, .gif, .or .tiff, will give you the smallest file size?
dimaraw [331]
.jpg will be the smallest size
3 0
3 years ago
Read 2 more answers
Describe the benefits of having an operational data warehouse (DWH), and the challenges of operating a DWH repository.
kvasek [131]

Answer:

The benefits of having the operational data ware-house are as follows:

  • The single operational warehouse typically support various tactical and the strategical decisions.  
  • It is subject oriented,volatile and integrated data warehousing in the system.
  • The warehousing mainly allow the system to process the large complex data in more efficient manner.
  • The operational warehouse are basically implemented for many business purposes.

The challenges of the operational warehouse repository are as follows:

  • In the operational data warehouse there is large number of user expectations.
  • The cost is the main challenge while designing the operational data warehousing as, it required efficient system in low cost.
  • Choosing the efficient and correct type of the warehouse is the big challenge.

5 0
3 years ago
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