Answer:
225 mL of water must be added.
Explanation:
First we <u>calculate how many HCl moles are there in 516 mL of a 0.191 M solution</u>:
- 516 mL * 0.191 M = 98.556 mmol HCl
Now we use that number of moles (that remain constant during the <em>dilution process</em>) to <u>calculate the final volume of the 0.133 M solution</u>:
- 98.556 mmol / 0.133 M = 741 mL
We can <u>calculate the volume of water required</u> from the volume difference:
Answer:
70.0°C
Explanation:
We are given;
- Amount of heat generated by propane as 104.6 kJ or 104600 Joules
- Mass of water is 500 g
- Initial temperature as 20.0 ° C
We are required to determine the final temperature of water;
Taking the initial temperature is x°C
We know that the specific heat of water is 4.18 J/g°C
Quantity of heat = Mass × specific heat × change in temperature
In this case;
Change in temp =(x-20)° C
Therefore;
104600 J = 500 g × 4.18 J/g°C × (x-20)
104600 J = 2090x -41800
146400 = 2090 x
x = 70.0479
=70.0 °C
Thus, the final temperature of water is 70.0°C
Answer:
basic
Explanation:
give me brainliest plz
it not neutral because anything with A pH of 7 is neutral. A pH less than 7 is acidic. A pH greater than 7 is basic.
