2) deposition and saponification
Answer:
3.6g
Explanation:
2 moles of water gives 1 mole of oxygen
2(h2o)=1(o2)
2(molar mass of h2o)=1(molar mass of oxygen molecule)
2(18)=1(16×2)
36=32
3.6=x
cross multiply
3.6×32=36× x
115.2=36x
x=115.2÷36
x=3.6g
Answer:
0.045 M/s
Explanation:
Given:
Initial concentration of A = 0.625 M
Final concentration of A = 0.100 M
Total time taken for the change of concentration = 11.6 seconds
The average rate of reaction is calculated as:
= 
on substituting the respective values, we get
= 
or
The average rate of reaction = 0.045 M/s