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lawyer [7]
3 years ago
14

How much water must be added to 516 mL of 0.191 M HCl to produce a 0.133 M solution? (Assume that the volumes are additive)

Chemistry
1 answer:
Alisiya [41]3 years ago
5 0

Answer:

225 mL of water must be added.

Explanation:

First we <u>calculate how many HCl moles are there in 516 mL of a 0.191 M solution</u>:

  • 516 mL * 0.191 M = 98.556 mmol HCl

Now we use that number of moles (that remain constant during the <em>dilution process</em>) to <u>calculate the final volume of the 0.133 M solution</u>:

  • 98.556 mmol / 0.133 M = 741 mL

We can <u>calculate the volume of water required</u> from the volume difference:

  • 741 mL - 516 mL = 225 mL
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