Question

How much water must be added to 516 mL of 0.191 M HCl to produce a 0.133 M solution? (Assume that the volumes are additive)

Answer 1

Answer:

225 mL of water must be added.

Explanation:

First we calculate how many HCl moles are there in 516 mL of a 0.191 M solution:

• 516 mL * 0.191 M = 98.556 mmol HCl

Now we use that number of moles (that remain constant during the dilution process) to calculate the final volume of the 0.133 M solution:

• 98.556 mmol / 0.133 M = 741 mL

We can calculate the volume of water required from the volume difference:

• 741 mL - 516 mL = 225 mL