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2 years ago

Find four different numbers in order from least to greatest that lie between -4.5 and -3.5

1 answer:

5 0

-4.4
-4.2
-4.0
-3.6

these are all between -4.5 and -3,5 I'm pretty sure, you can check by making a number line and plotting all the points to see if they stay between -4.5 and -3.5

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Please answer this. thank you

Rama09 [41]

Answer: $(-\infty, -4]$

Curved parenthesis at negative infinity

Square bracket at -4

====================================================

Work Shown:

$5(x+4) \le 0 \\\\x+4 \le \frac{0}{5} \\\\x+4 \le 0 \\\\x \le 0-4 \\\\x \le -4 \\\\$

The last inequality shown above is the same as saying $-\infty < x \le -4$

Converting this to interval notation leads to the final answer of $(-\infty , -4]$

Note the use of a square bracket at -4 to include this endpoint. We can never include either infinity, so we always use a parenthesis for either infinity.

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2 years ago

Is proportional or not?

Eduardwww [97]

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2 years ago

What is 639.497 rounded to the nearest tenth

makkiz [27]

It'll be 639.500 or just 639.5

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2 years ago

What are the dimensions (length and width) if the poster is enlarged by a factor of 1.5 ? (Remember multiply the factor by the d

Veseljchak [2.6K]

Use socratic or photomath

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3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

2 years ago