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3 years ago

15

Four-fifths of a spinach casserole is leftover after Sam has lunch. Jackie and Alicia each take 1/2 of the leftover casserole. J

ackie eats only 3/4 of her portion
What fraction of a whole casserole did Jackie eat? Express your answer as a simplified fraction.

1 answer:

Delvig [45]3 years ago

3 0

Answer:legit?

Step-by-step explanation:legit?

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Help me plz u will make my day

oksian1 [2.3K]

Answer:

18 1/3. You add 18 1/3 to cancel out that number.

Step-by-step explanation:

5 0

3 years ago

Solve the equation <br> -3 2/3+b = 8 1/5<br><br> B= 5 3/5<br> B= 4 4/5<br> B= 11 3/5<br> B= 11 1/5

Readme [11.4K]

Answer:

11 13/15

Step-by-step explanation:

-3 2/3+b = 8 1/5

Add 3 2/3 to each side

-3 2/3 + 3 2/3+b = 8 1/5+ 3 2/3

b = 8 1/5 + 3 2/3

We need to get a common denominator of 15

8 1/5 = 8 3/15

3 2/3 = 3 10/15

----------------

11 13/15

4 0

3 years ago

Copy and complet the table compare the values of 2^x-2 with the values of 2^x-2

Vladimir79 [104]

#2^(x-2)

For 2

2^(2-2)=2⁰=1

For 3

2^(3-2)=2

For 4

2^(4-2)=2²=4

For 5

2^{5-2}=2³=8

For 6

2^{6-2}=2⁴=16

#2^x-2

For 2

2²-2=2

For 3

2³-2=6

For 4

2⁴-2=14

For 5

2⁵-2=30

For 6

2⁶-2=62

3 0

1 year ago

Read 2 more answers

Which one should i pick?

Airida [17]

last one is the solution u should choose

7 0

3 years ago

Read 2 more answers

The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a

Evgesh-ka [11]

The complete question is as follows.

The equation a = $\frac{1}{2}(b_1 + b_2 )h$ can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, $b_1$ and $b_2$ . Which are equivalent equations?

(a) $\frac{2a}{h} - b_2 = b_1$

(b) $\frac{a}{2h} - b_2 = b_1$

(c) $\frac{2a - b_2}{h}$ = $b_1$

(d) $\frac{2a}{b_1 + b_2} = h$

(e) $\frac{a}{2(b_1 + b_2)}$ = h

Answer: (a) $\frac{2a}{h} - b_2 = b_1$ ; (d) $\frac{2a}{b_1 + b_2} = h$ ;

Step-by-step explanation: To determine $b_1$ :

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = ( $b_1 + b_2$ )h

$\frac{2a}{h} = b_1 + b_2$

$\frac{2a}{h} - b_2 = b_1$

To determine h:

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{(b_1 + b_2)}$ = h

To determine $b_2$

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{h} = (b_1 + b_2)$

$\frac{2a}{h} - b_1 = b_2$

Checking the alternatives, you have that $\frac{2a}{h} - b_2 = b_1$ and $\frac{2a}{(b_1 + b_2)}$ = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0

3 years ago