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2 years ago

Kyle leaves a 15% tip for lunch bill of $12 what amount tip does Kyle leave

Mathematics

2 answers:

Aleonysh [2.5K]2 years ago

8 0

Kyle leaves 1.80 because you have to do 0.15*12

Sunny_sXe [5.5K]2 years ago

4 0

Kyle leaves $1.8 because 15% of $12 is $1.8

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Easyy I need help guys...(easy fractions)

Ivanshal [37]

1a. 5/10 can be simplified to 1/2. (5 divided by 5 is one, 10 divided by 5 is 2.)

1b. 9/12 can be simplified to 3/4. (9 divided by 3 is 3, 12 divided by 3 is 4.)

1c. 12/18 can be simplified to 2/3. (12 divided by 6 is 2, 18 divided by 6 is 3.)

1d. 9/24 can be simplified to 3/8. (9 divided by 3 is 3, 24 divided by 3 is 8.)

1e. 27/90 can be simplified to 3/10. (27 divided by 9 is 3, 90 divided by 9 is 10.)

1f. 40/48 can be simplified to 5/6. (40 divided by 8 is 5, 48 divided by 8 is 6.)

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2 years ago

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The sum of two numbers is x. If one of the numbers is 12, what is the other ?

Vlad1618 [11]

If the sum of two numbers is x

Then the equation is like this:

a+b = x

Then it says one of the number is 12. Change either a or b into 12

12 + b =x

If we want to find the other number, we need the make it into the subject

b = x - 12

Hope that help.

6 0

3 years ago

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Please help me someone

nlexa [21]

Base = 5 * 12 = 60 in^2

Height = 4 in

Perimeter is the sum of all straight

Perimeter = 20 + 16 + 48

Perimeter = 84 in

Perimeter of base = 12 * 2 + 5 * 2 = 34

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2 years ago

What is the value of x? Leave your answer in simplest radical form.

OleMash [197]

Step-by-step explanation:

By using Pythagoras theoram,

x²= (6)²+(4)²

${x}^{2} = 36 + 16$

${x}^{2} = 52$

$x = \sqrt{52}$

$x = 2 \sqrt{13}$

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2 years ago

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A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t

Licemer1 [7]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which this amount changes over time is given by the ODE

$A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$

$A'(t)+\dfrac1{100}A(t)=15$

We're told that the tank initially starts with no salt in the water, so $A(0)=0$ .

Multiply both sides by an integrating factor, $e^{t/100}$ :

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}$
$\left(e^{t/100}A(t)\right)'=15e^{t/100}$
$e^{t/100}A(t)=1500e^{t/100}+C$
$A(t)=1500+Ce^{-t/100}$

Since $A(0)=0$ , we have

$0=1500+C\implies C=-1500$

so that the amount of salt in the tank over time is given by

$A(t)=1500(1-e^{-t/100})$

After 10 minutes, the amount of salt in the tank is

$A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}$

8 0

2 years ago