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2 years ago

Approximately how many pages would ms jackson need to translate to earn 750

Mathematics

1 answer:

NeTakaya2 years ago

7 0

Supposing a linear model, it is found that Jackson would need to translate 2500 pages to earn $750.

<h3>What is a linear function?</h3>

A linear function is modeled by:

$y = mx + b$

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0.

In this problem, we suppose that:

He earns a salary of $500, hence b = 500.

He earns $0.1 per page translated, hence m = 0.1.

Thus, his salary as a function of the number of pages translated x is given by:

$y = 0.1x + 500$

When he earns $750, y = 750, hence:

$y = 0.1x + 500$

$750 = 0.1x + 500$

$0.1x = 250$

$x = \frac{250}{0.1}$

$x = 2500$

Jackson would need to translate 2500 pages to earn $750.

You can learn more about linear functions at brainly.com/question/24808124

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Which function represents a vertical stretch of an exponential function?

nika2105 [10]

Answer:

A. $f(x)=3(\frac{1}{2})^x$

Step-by-step explanation:

The options are:

$A. f(x)=3(\frac{1}{2})^x\\\\B. f(x)=\frac{1}{2}(3)^x\\\\C. f(x)=(3)^{2x}\\\\ D. f(x)=3^{(\frac{1}{2}x)}$

For this exercise it is important to remember that, by definition, the Exponential parent functions have the form shown below:

$f(x) = a^x$

Where "a" is the base.

There are several transformations for a function f(x), some of those transformations are shown below:

1. If $bf(x)$ and $b>1$ , then the function is stretched vertically by a factor of "b".

2. If $bf(x)$ and $0$ , then the function is compressed vertically by a factor of "b"

Therefore, based on the information given above, you can identify that the function that represents a vertical stretch of an Exponential function, is the one given in the Option A. This is:

$f(x)=3(\frac{1}{2})^x$

Where the factor is:

$b=3$

And $3>1$

7 0

2 years ago

Read 2 more answers

6x + 12 + 2x - 4 <br> Can u help me pls

Ray Of Light [21]

Answer:

8x+8

Step-by-step explanation:

6x+2x=8x 12-4=8

3 0

2 years ago

On a social studies test, James scored a 2025, Jules earned an 81%, and Scott scored a 0.815. Who earned the highest grade? Just

Airida [17]

Answer:

Scott

Step-by-step explanation:

20/25=.8 .8=80%

.815*100=81.5%

81%

After finding a decimal and multiplying by 100, you get the percent so you can compare. 81.5% is the highest, so Scott had the highest score.

Hope this helps. Please put brainliest if you can!

7 0

3 years ago

Create a real world example for each of the words and the words are expressions, equations, inequalities.

d1i1m1o1n [39]

Expression: 5+5
Equation: 5a + 2b =5
Inequality: 2x > 2+5

6 0

3 years ago

Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample

puteri [66]

Answer:

i $\to$ a

$n = 96040000$

i $\to$ b

$n_1 =24010000$

i $\to$ c

$n_2 =41602500$

ii $\to$ a

$E = 58.16$

ii $\to$ b

$291.84 < \mu < 408.16$ \

ii $\to$ c

There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

The sample size is $n = 8$

The sample mean is $\= x = \$ 350$

The sample standard deviation is $\$ 100$

Considering question i

i $\to$ a

At $E = 0.02$

given that the confidence level is 95% = 0.95

the level of significance would be $\alpha =1-0.95 = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha }{2} } = 1.96$

So the sample size is mathematically evaluated as

$n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2$

=> $n =[ \frac{ 1.96 * 100}{ 0.02} ]^2$

=> $n = 96040000$

i $\to$ b

At $E_1 = 0.04$ and confidence level = 95% => $\alpha_1 = 0.05$ => $Z_{\frac{\alpha_1 }{2} } = 1.96$

$n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2$

=> $n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2$

=> $n_1 =24010000$

i $\to$ c

At $E_2 = 0.04$ confidence level = 99% => $\alpha_2 = 0.01$

The critical value of $\frac{\alpha_2 }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha_2 }{2} } = 2.58$

=> $n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2$

=> $n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2$

=> $n_2 =41602500$

Considering ii

Given that the level of significance is $\alpha = 0.10$

Then the critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{100 }{\sqrt{8} }$

$E = 58.16$

Generally the 90% confidence interval is mathematically evaluated as

$\= x - E < \mu < \= x + E$

=> $350 - 58.16 < \mu < 350 + 58.16$

=> $291.84 < \mu < 408.16$

So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

8 0

3 years ago