<img src="https://tex.z-dn.net/?f=x%20%20%5Cdiv%203x%20-%202%20%3D%201%20%5Cdiv%203x%20-%204" id="TexFormula1" title="x \div 3x

All categories

WARRIOR [948]

3 years ago

- 2 = 1 \div 3x - 4" alt="x \div 3x - 2 = 1 \div 3x - 4" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Maurinko [17]3 years ago

4 0

Hello from MrBillDoesMath!

Answer:

x = 1/2 (1 +\- i sqrt(23))

Discussion:

x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)

1 \3x - 4 = (1/3)x - 4 (**)

(*) = (**) =>

(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3

x^2 - 6 = x - 12 => subtract x from both sides

x^2 -x -6 = -12 => add 12 to both sides

x^2-x +6 = 0

Using the quadratic formula gives:

x = 1/2 (1 +\- i sqrt(23))

Thank you,

MrB

You might be interested in

If a rectangle has a base of 6 units, and a height of 8 units, what is its area?

Morgarella [4.7K]

Answer:

a=48 units^2

Step-by-step explanation:

The area of a rectangle can be found using:

a=bh

We know the base is 6, and the height is 8, so we can substitute them in

a=6*8

a=48

Area uses units squared, so,

a=48 units^2

4 0

4 years ago

Read 2 more answers

(6(1) = -5 1) Find (4) in the sequence given by (6(n) = b(n − 1) +9

Sloan [31]

Answer:

f(4) = 22

Step-by-step explanation:

I think that you type wrongly.

we have f(1) = -5

and f(n) = f(n-1) + 9

Find f(4)

Then

with n= 2 we have f(2) = f(1) + 9 = - 5+ 9= 4

with n= 3 we have f(3) = f(2) + 9 = 4 + 9= 13

and finally with n= 4 we find f(4) = f(3) + 9 = 13+ 9= 22

So f(4) = 22

Hope you understand.

8 0

3 years ago

Read 2 more answers

the graph of a linear function is given below. What is the zero of the function? a) -5. b) 2/5. c) 2. d) 5/2

Murrr4er [49]

The zero of a function is the x-value at which the function value is zero. That is, the value of the function that intersects the x-axis. From the picture, the zero is -5

4 0

2 years ago

Could I have some help on my patterns assignment

nydimaria [60]

Answer:

1. 13, 18, 23, 28, 33, 38, 43, 48, 53

Conjecture: Each term is 5 more than the previous term.

2. 512, 256, 128, 64, 32, 16, 8, 4, 2

Conjecture: Each term is half of the previous term.

3. 1, 8, 27, 64, 125, 216, 343, 512, 729

Conjecture: Each term is a cube. To find the nth term, cube n.

4. 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

Conjecture: Each term is the next consecutive prime number.

5. Correct as is

6. 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89

Conjecture: Each term is the sum of the 2 previous numbers.

Step-by-step explanation:

Given: 13, 18, 23, 28

We add 5 to each number

13 + 5 = 18

18 + 5 = 23

23 + 5 = 28

28 + 5 = 33

33 + 5 = 38

38 + 5 = 43

43 + 5 = 48

48 + 5 = 53

Given : 512, 256, 128, 64

Divide each number by 2

512 ÷ 2 =256

256 ÷ 2 = 128

128 ÷ 2 = 64

64 ÷ 2 = 32

32 ÷ 2 = 16

16 ÷ 2 = 8

8 ÷ 2 = 4

4 ÷ 2 = 2

Given: 1, 8, 27, 64

We have to cube n:

n³ = consecutive number cubed

1³ = 1 or 1 × 1 × 1

2³ = 8 or 2 × 2 × 2

3³ = 27 or 3 × 3 × 3

4³ = 64 or 4 × 4 × 4

5³ = 125 or 5 × 5 × 5

6³ = 216 or 6 × 6 × 6

7³ = 343 or 7 × 7 × 7

8³ = 512 or 8 × 8 × 8

9³ = 729 or 9 × 9 × 9

Consecutive prime number: Consecutive prime numbers are those that have no gaps or prime numbers between them.

Look at the picture in the link:

Given: 1, 1, 2, 3, 5, 8

We must add the two previous numbers to get the next term:

1 + 1 = 2

1 + 2 = 3

2 + 3 = 5

3 + 5 = 8

5 + 8 = 13

8 + 13 = 21

13 + 21 = 34

21 = 34 = 55

34 + 55 = 89

8 0

2 years ago

S=2WH+2WL+2HL SOLVE FOR L

RSB [31]

$2WH+2WL+2HL=S\\\\2WL+2HL=S-2WH\\\\L(2W+2H)=S-2WH\\\\\boxed{L=\frac{S-2WH}{2W+2H}}$

6 0

3 years ago