Question

#1. bring the fraction: b / 7a^2c to a denominator of 35a^3c^3

Answer 1

Part A: Term $5ac$ is used to bring denominator of $35a^{3} c^{3}$

Part B: Term $a+4$ is used to bring denominator of $16-a^{2}$

Explanation:

Part A: To bring the fraction $\frac{b}{7a^{2}c }$ to a denominator of $35a^{3} c^{3}$, we need to multiply the denominator by the term $5ac$

The term $5ac$ is determined by $\frac{35a^{3} c^{3}}{7a^{2}c }}$ which equals $5ac$

Thus, the fraction becomes

$\frac{b}{7a^{2}c }\times\frac{5ac}{5ac} =\frac{5abc}{35a^{3} c^{3}}$

Thus, the term $5ac$ is used to bring denominator of $35a^{3} c^{3}$

Part B: To bring the fraction $\frac{a}{a-4}$ to a denominator of $16-a^{2}$, we need to multiply the denominator by $a+4$

Thus, we have,

$\frac{a}{a-4}\times\frac{a+4}{a+4} =\frac{a(a+4)}{16-a^{2}}$

Thus, the term $a+4$ is used to bring denominator of $16-a^{2}$