a vehicle moving at a constant speed travels 45 miles in 3/4 hour. the driver thinks he will be late to a meeting that is still
65 miles away and starts in 1.25 hours. assume he maintains a constant speed. find the drivers unit rate of speed and explain wether he was late or not.
First we rearrange by using the definition of between. AB=x+10, BC=x+14, AC=22 Given that AB+BC=AC, we can solve for X (X+10)+(X+14)=22 X+10+X+14=22 2X+24=22 2X+24-24=22-24 2X=-2 2X/2=-2/2 X= -1