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vodomira [7]
4 years ago
12

What is the distance from b (-35,25) to c (-20, 15)

Mathematics
1 answer:
Natali5045456 [20]4 years ago
6 0

Answer:

d = 5\sqrt{13}

Step-by-step explanation:

Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>:

d = \sqrt{(-20-(-35))^2+(15-25)^2}

d = \sqrt{(-20+35)^2+(-10)^2}

d = \sqrt{(15)^2+100}

d = \sqrt{225+100}

d = \sqrt{325}

d = 5\sqrt{13}

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Solve for x:
4 (6 x + 1) - 3 (4 x + 3) = 43
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4 (6 x + 1) = 24 x + 4:
24 x + 4 - 12 x - 9 = 43
Grouping like terms, 24 x - 12 x - 9 + 4 = (24 x - 12 x) + (4 - 9):
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24 x - 12 x = 12 x:
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4 - 9 = -5:
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12 x + (5 - 5) = 5 + 43
5 - 5 = 0:
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Divide both sides of 12 x = 48 by 12:
(12 x)/12 = 48/12
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x = 48/12
The gcd of 48 and 12 is 12, so 48/12 = (12×4)/(12×1) = 12/12×4 = 4:
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