Answer:
s(2) = 7.75
Step-by-step explanation:
given the velocity v(t) = t^3
we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.

Now we can use this value of t to formulate the position function s(t):

this is the position at time t.
to find the position at t=2



the position of the particle at time, t =2 is s(2) = 7.75
Your answer would be (w+2)(w−10). If you want me to explain please don't hesitate to ask.
Answer:
uh please provide a question
Answer:
Number one! :D
Step-by-step explanation:
3
−
1
=
3
−
1
3
−
1
+
1
=
3
−
1
+
1
0
=
0
Answer:
The circle in graph as radius = 4 and center O(2, 3)
=> equation of this circle: (x - 2)^2 + (y - 3)^2 = 4^2 = 16
=> Option C is correct
Hope this helps!
:)