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Furkat [3]
2 years ago
7

HURRY 1.3(2x + 4) + 2(3x – 4) 2. Evaluate the expression for x=5

Mathematics
2 answers:
____ [38]2 years ago
5 0

Answer:

According to my evaluations this equation is very petty and most likely has an answer. There are variables and numbers "3x". This part of the equation makes me feel special because 3 is a prime number. It is also mysterious because we dont know for sure what x is. This equation teaches the mathematician the true meaning of life. As it demonstrates the complexity, the information you know for sure and the information that you will learn in the future. The reader will also learn that not all problems can be solved and the ones that can be solved should be solved with varying difficulty. Finally the individual will realize that everyone has their own method to solve problems and go about life. In conclusion, this pretty equation teaches the mathematician about the importance of hard work and acceptance of everyone in their community.

Pie2 years ago
3 0

Answer:

8.6x-2.8

Step-by-step explanation:

Also i feel like ik u from school or something.

There was this girl who had the exact last name and first name

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Help help help help pls
Yanka [14]

Answer:

x - 3 > 10

Step-by-step explanation:

3 0
3 years ago
What does x equal in 5-4(-x-3/2)5(-6x-6/5)+10x
kondaur [170]

Answer:

Step-by-step explanation:

4 0
3 years ago
For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work.
11Alexandr11 [23.1K]
Since we know x=6, replace all the x with 6 in the equation and then follow the PEMDAS rule. y= -2(6)^2 + 2(6) + 2 y= -2 (36) + 2 (6) + 2 y= -72 + 12 + 2 y= -60+2 y= -58
7 0
3 years ago
If f(x) = x^2 – 25 and g(x) = x – 5, what is the domain of (f/g)(x)
daser333 [38]
(f/g)(x) = (x^2-25)/(x-5) = x+5. So domain will be R, all real numbers
4 0
3 years ago
Read 2 more answers
Show that any number of the form ABCABC (e.g. 356356) is divisible by 13.
Shtirlitz [24]

We could write such a number as

10^5a+10^4b+10^3c+10^2a+10b+c

=10^2(10^3+1)a+10(10^3+1)b+(10^3+1)c

=(10^3+1)(100a+10b+c)

10^3+1=1001=13\cdot77 so we're done.

8 0
3 years ago
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