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Nonamiya [84]
2 years ago
12

Please help me:What's the domain?What's the range?Is it a function?​

Mathematics
2 answers:
VladimirAG [237]2 years ago
6 0

Answer:

\displaystyle Yes \\ Range: Set-Builder\:Notation → [f(x)|-2 ≤ f(x) ≤ 4] \\ Interval\:Notation → [-2, 4] \\ \\ Domain: Set-Builder\:Notation → [x|0 ≤ x ≤ 7] \\ Interval\:Notation → [0, 7]

Step-by-step explanation:

Just by looking at the graph vertically and horisontally, you can tell what the range and domain is, depending on whether the segments are <em>closed</em> or <em>opened</em>.

* This is a function because it passes the <em>vertical</em><em> </em><em>line test</em>.

** This is kind of like a sine wave.

I am joyous to assist you anytime.

anzhelika [568]2 years ago
4 0

Answer:

  • domain: [0, 7]
  • range: [-2,4]

Step-by-step explanation:

The domain is the horizontal extent of the graph. That is from x=0 to x=7.

The range is the vertical extent of the graph. The low point appears to be near y=-2, and the high point appears to be about y=4.

The intervals can be written as ...

 domain: [0, 7]

  range: [-2, 4]

_____

The curve passes the "vertical line test", so IS A FUNCTION. (It does not intersect any vertical line more than once.)

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Question 2*
lilavasa [31]

Answer:

The average rate of change between these times is 68 miles per hour

Step-by-step explanation:

Here, we are to determine the average rate of change between hour 2 and hour 7

The distance traveled at hour 2 is 140 miles

The distance traveled at hour 7 is 480 miles

So we can say we have two points and we want to know the rate of change between these points

Mathematically, we can represent the rate of change as Δ

Thus, between the two different times, we have;

Δ = (D7-D2)/(T7-T2)

where (T7,D7) = (7,480) and (T2,D2) = (2,140) represents the time and distance at hour 2 and hour 7 respectively

Now inputing the values into the equation, we have;

Δ = (480-140)/(7-2) = 340/5 = 68 miles/hour

3 0
2 years ago
Write as a single power: 4​^20​ + 4​^20​ + 4^​20​ + 4^​20
S_A_V [24]
Sorry, I misinterpreted the question before.\\\\ 4^20+4^20+4^20+4^20 \\\\ 4(4^20)\\\\ 4^21\\\\
3 0
3 years ago
Suppose an ant walks counterclockwise on the unit circle from the point to the endpoint of the radius that forms an angle of rad
serg [7]

Answer:

\frac{4\pi}{3}

Step-by-step explanation:

The original questions is suppose an ant walks counterclockwise on a unit circle from the point (1,0) to the endpoint of the radius that forms an angle of 240 degrees with the positive horizontal axis.

To find the distance ant walked we find the arc length of the sector with central angle 240 degree and radius =1 (unit circle)

arc length of a sector =\frac{centralangle}{360} \cdot 2\pi r

arc length of a sector =\frac{240}{360} \cdot 2\pi(1)

arc length of a sector =\frac{2}{3} \cdot 2\pi

\frac{4\pi}{3}

6 0
3 years ago
Write this trinomial in factored from 6a^2-17a+7
timama [110]

Answer:

(3a-7) (2a-1) is the answer

Step-by-step explanation:

8 0
3 years ago
Find the angles in this quadilateral
ch4aika [34]

Answer:

Therefore a= 90°,b=54°, x=54°, y= 162°

Step-by-step explanation:

a=90°

a:b=5:3

5+3= 8

5/8 x A = 90

A is the sum of the angles of a and b divided in the ratio 5:3

5A/8 = 90

cross multiply

5A= 90 X8 = 720

5A=720

A= 720/5= 144°

b= 3/8 x 144 = 3x144/8 = 432/8 = 54

a= 90

b= 54

x:y is in the ratio of 1:3

the Sum of angles in a Quadrilateral is 360°

if the sum of a and b is 144°

then the reamining angles is 360-144= 216°

then x:y=1:3

1+3=4

x= 1/4 x 216= 54°

y= 3/4 x 216= 162°

Therefore a= 90°,b=54°, x=54°, y= 162°

we can see that b = x = 54°

7 0
3 years ago
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