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3 years ago

Molly played an online game three times.Her score were 5.5. -3.6 and 12.8.What was her average score for the three games?

Mathematics

1 answer:

zalisa [80]3 years ago

5 0

Answer:

Her average was 4.9 for all three games.

Step-by-step explanation:

(5.5 + -3.6 + 12.8)/3

14.7/3

4.9

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In a school egg drop challenge 136 of the eggs broke out of 200 total what percent of eggs survived the drop ?

dusya [7]

To make this equation easier, we can just divide the data by 2, so that the exact number of eggs that survived, is the percentage that survived.

Explanation:

200 = 200 Total Eggs

136 = 136 Eggs That Broke

So, the ratio of eggs that broke to total eggs is:

136 / 200

So, subtract the number of eggs that broke to the total eggs, to find the amount that survived.

200 - 136 = 64

So now we know that, 64 eggs of 200 survived.

Which means, that 32% off the eggs had survived.

4 0

2 years ago

Read 2 more answers

How can i show my work for 2x-4= -10+x

Anuta_ua [19.1K]

Let me help you with that :)

2x - 4 = - 10 + x (we transfer the x from the right side, and transfer the - 4 from the left side)

2x - x = - 10 + 4 (we calculate this)

x = -6

And that is the answer; x = - 6 :)

8 0

3 years ago

Luke bought 256 ounces of strawberries. he divided them evenly between 8 different pies.

pychu [463]

Answer:

2 pounds.

Step-by-step explanation:

We have been given that Luke bought 256 ounces of strawberries. He divided them evenly between 8 different pies. We are asked to find the pounds of strawberries that Luke put on each pie.

First of all, we will convert 256 ounces into pounds.

We know that 1 pound equals 16 ounces. To convert 256 ounces into pounds, we need to divide 256 by 16.

$256$ $ounces=\frac{256}{16}$ $pounds=16$ $pounds$

Now we will divide 16 pounds by 8 to find number of strawberries put on each pie.

$Pounds$ $of$ $strawberries$ $on$ $each$ $pie=\frac{16}{8}$

$Pounds$ $of$ $strawberries$ $on$ $each$ $pie=2$

Therefore, Luke put 2 pounds strawberries on each pie.

3 0

2 years ago

A study shows that 78% of the population of all calculus students consider calculus an exciting subject. Suppose 20 students ar

alexdok [17]

Answer:

0.046145 = 4.6145%

Step-by-step explanation:

We need to find the probability of 19 or 20 (all) students considering calculus to be an exciting subject, so first we find the probability for 19 students, then for 20 students, and we sum these probabilities.

The probability of the student NOT considering calculus to be an exciting subject is 1 - 0.78 = 0.22

For 19 students, we also have to calculate a combination of 20 choose 19, as these 19 students can be in different "position" among the 20 students, so:

C(20,19) = 20!/19! = 20

Probability of 19 students considering calculus to be an exciting subject:

C(20,19) * 0.78^19 * 0.22^1 = 0.039196756

Probability of 20 students considering calculus to be an exciting subject:

C(20,20) * 0.78^20 = 1 * 0.78^20 = 0.006948516

The final probability is:

0.039196756 + 0.006948516 = 0.046145272 = 4.6145272%

Rounding to six decimal places: 0.046145 = 4.6145%

5 0

3 years ago

In a candy bar, 165 calories are from sugar. There are 250 calories in the candy bar. What percent of the calories are from suga

stiv31 [10]

165/200=33/40
33/40=0.825
0.825=82.50%
Hope this helps

5 0

3 years ago

Read 2 more answers