Yo can anyone help???

The student council sold jars of mixed nuts at their bazaar they were given 40 empty jars. They paid $19.60 for the nuts and $11

Alex Ar [27]

Answer:

$\$1.75$

Step-by-step explanation:

Total amount paid for the nuts is $19.60

Total amount paid for the ribbons is $11.20

Profit made on each jar is 98￠= $0.98

Cost price of the nuts and ribbon for the 40 jars is $19.6+11.2=\$30.8$

Cost price for nuts and ribbonn for one jar = $\dfrac{30.8}{40}=\$0.77$

Selling price is the sum of the cost price and profit.

Selling price for one jar = $0.77+0.98=\$1.75$

They charged $\$1.75$ for each jar.

3 0

2 years ago

Which rational exponent represents a square root? A. 1 / 2 B. 3/2 C. 1/3 D. 1/4

Fofino [41]

Answer:

1/2 rational exponent represents a square root.

Therefore, option A is correct.

Step-by-step explanation:

As we know that raising to the one-half power i.e. $\frac{1}{2}$ is the same

as taking the square root.

so $x^{\frac{1}{2}}$ is the same as the square root of $x$ .

For example, taking the square root of 4 will determine:

$4^{\frac{1}{2}}$

$\mathrm{Factor\:the\:number:\:}\:4=2^2$

$4^{\frac{1}{2}}=\left(2^2\right)^{\frac{1}{2}}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0$

$\left(2^2\right)^{\frac{1}{2}}=2^{2\cdot \frac{1}{2}}$

so the expression becomes

$4^{\frac{1}{2}}=2^{2\cdot \:\frac{1}{2}}$

$=2^1$

$=2$ ∵ $\mathrm{Apply\:exponent\:rule}:\quad \:a^1=a$

so, 1/2 rational exponent represents a square root.

Therefore, option A is correct.

5 0

2 years ago

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A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

5 0

2 years ago

A clothing store spends $15 for each sweatshirt it produces and has fixed

lys-0071 [83]

Answer:

The cost of each sweatshirt in order to break even is $25

Step-by-step explanation:

Given as :

The amount that store spend on each sweatshirt = $15

The fixed cost for production = $600

The total number of sweatshirt that store makes = 60

Let The price of each sweatshirt = $A

Now, According to question

∵ each sweatshirt cost $15 , and number of shirt made is 60

∴ The money spend on making 60 shirts = $15 × 60

i.e The money spend on making 60 shirts = $900

Again

The fixed cost for production = $600

So,Total money spend on shirt making = fixed cost + price on making 60 shirts

i.e Total money spend on shirt making = $600 + $900

Or, Total money spend on shirt making = $1500

Again

The price of each sweatshirt = $\dfrac{\textrm total money spend on making shirt}{\textrm number of shirts}$

Or, A = $\dfrac{1500}{60}$

∴ Amount = $25

So, The cost of each sweatshirt = A = $25

Hence, The cost of each sweatshirt in order to break even is $25 . Answer

7 0

2 years ago

A=36 a=8 b=5 find C.

Inessa [10]

Could you please elaborate on this equation

8 0

2 years ago

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